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Genrish500 [490]
2 years ago
8

write the balanced net ionic equation for the reaction of aqueous sodium sulfide with aqueous lead(II) nitrate

Chemistry
1 answer:
ryzh [129]2 years ago
7 0

The balanced net ionic equation for the reaction of aqueous sodium sulfide with aqueous lead(II) nitrate is Pb2+(aq) + S2-(aq) ===> PbS(s).

The chemical equation known as the net ionic equation only displays the substances that are directly involved in the chemical process. It is described how to write a net ionic equation. We only need to take out the spectator ions in order to formulate the net ionic equation. We are left with the net ionic equation after removing the spectator ions! The net ionic equation can be obtained by repeating this procedure for any reaction.

Na2S(aq)   +   Pb(NO3)2(aq)   ===>   2NaNO3(aq)   +   PbS(s)  ...  molecular equation

sodium sulfide....lead(II) nitrate .........sodium nitrate.....lead sulfide

2Na+(aq) + S2-(aq) + Pb2+(aq) + 2NO3-(aq) ==> 2Na+(aq) + 2NO3-(aq) + PbS(s) ...  complete ionic equation

Pb2+(aq) + S2-(aq) ===> PbS(s)  ...  net ionic equation

To know more about net ionic equation refer to:  brainly.com/question/22885959

#SPJ4

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