Hello!
First, we need to determine the pKa of the base. It can be found applying the following equation:
Now, we can apply the
Henderson-Hasselbach's equation in the following way:
![pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%20%5Cfrac%7B%5BCH_3NH_2%5D%7D%7B%5BCH_3NH_3Cl%5D%7D%20%29%3D10%2C65%2Blog%28%20%5Cfrac%7B0%2C18M%7D%7B0%2C73M%7D%20%29%3D10%2C04)
So,
the pH of this buffer solution is 10,04Have a nice day!
In this question, the patient needs to be given exactly <span>1000ml </span>of a 15.0%. The content of the glucose should be:
weight= volume * density* concentration
1000ml * 1mg/ml *15%= 150mg.
The stock solution is 35%, then the amount needed in ml would be:
weight= volume * density* concentration
150mg= volume * 1mg/ml *35%
volume= 150/35%= 3000/7= 428.5ml
I don’t know is this science ??
homogeneous mixture not pure, but is spread out the same throughout
concentration, a measure of the amount of solute dissolved in a solvent
mixture,two or more substances that do not chemically combine, salt and pepper
solute,substance that is dissolved in the solution
Acceleration is change in velocity (or speed) divided by time, so your answer is C.change in speed divided by time.
