Answer:
3 m/s²
Explanation:
acceleration = Force / mass; 4.5/1.5 = 3
Answer:

Explanation:
given,
J = 50 kg-m²
frequency, f = 20 Hz
time ,t = 5 s
we know,
angular velocity = 2 π f
ω = 2 π x 20
ω = 125.66 rad/s
now, angular acceleration calculation


α = 25.13 rad/s²
Torque given to the flywheel.



Torque of the given flywheel is equal to 
Explanation:
It is given that,
Radius of bowl, r = 3 m
A small block is released from rest from the edge of a large hemispherical friction less bowl. Let v is the speed of the mass when it passes through the bottom of the bowl and u is the initial speed of the mass, u = 0. Using conservation of energy as :

h = r = 3 m


v = 7.66 m/s
or
v = 7.7 m/s
So, the speed of the mass at the bottom of the bowl is 7.7 m/s. Hence, this is the required solution.