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ValentinkaMS [17]
3 years ago
7

A flywheel of J = 50 kg-m2 initially standing still is subjected to a constant torque. If the angular velocity reaches 20 Hz in

5 S, find the torque given to the flywheel.
Physics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

\tau = 1256.5\ N.m

Explanation:

given,

J = 50 kg-m²

frequency, f = 20 Hz

time ,t = 5 s

we know,

angular velocity = 2 π f

ω = 2 π x 20

ω = 125.66 rad/s

now, angular acceleration calculation

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{125.66-0}{5}

   α = 25.13 rad/s²

Torque given to the flywheel.

    \tau = I \alpha

    \tau = 50\times 25.13

    \tau = 1256.5\ N.m

Torque of the given  flywheel is equal to \tau = 1256.5\ N.m

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