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ValentinkaMS [17]
3 years ago
7

A flywheel of J = 50 kg-m2 initially standing still is subjected to a constant torque. If the angular velocity reaches 20 Hz in

5 S, find the torque given to the flywheel.
Physics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

\tau = 1256.5\ N.m

Explanation:

given,

J = 50 kg-m²

frequency, f = 20 Hz

time ,t = 5 s

we know,

angular velocity = 2 π f

ω = 2 π x 20

ω = 125.66 rad/s

now, angular acceleration calculation

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{125.66-0}{5}

   α = 25.13 rad/s²

Torque given to the flywheel.

    \tau = I \alpha

    \tau = 50\times 25.13

    \tau = 1256.5\ N.m

Torque of the given  flywheel is equal to \tau = 1256.5\ N.m

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3 years ago
Determine whether or not each of the following statement is true. If a statement is true, prove it. If the statement is false, p
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True

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On earth, two parts of a space probe weigh 14500 N and 4800 N. These parts are separated by a center-to-center distance of 18 m
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Answer:

F = 1.489*10^{-7}  N

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W= weight of the object( in N)

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Force between these two objects is given by:

F =  \frac{Gm_{1} m_{2}}{R^{2} }

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R= distance between their centres (in m)(18 m)

Substituiting all these values into the above formula

F = 1.489*10^{-7}  N

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3 years ago
A bullet with a mass of 0.1 kg is travelling at
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The block with the bullet lodged in the block is now travelling at 2.133 m/s.

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When there is no external force acting on the system, the momentum remains conserved.

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Thus, the  block with the bullet lodged in block now travelling at 2.133 m/s.

Learn more about momentum conservation principle.

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