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Mice21 [21]
3 years ago
14

What is 65x2? .....talk too meeee!! lm.ao I’m hella bored:)

Chemistry
2 answers:
Morgarella [4.7K]3 years ago
7 0
130 hope this helps
Natali [406]3 years ago
4 0

Answer:

130

Explanation:

jaja lol I don't think this is a site for conversations

You might be interested in
A 6.40 g sample of a compound is burned to produce 8.37 g CO_2, 2.75 g H_2O, 1.06 g N_2, and 1.23 g SO_2. What is the empirical
LuckyWell [14K]

The empirical formula :

C₁₀H₁₆N₄SO₇

<h3>Further explanation</h3>

Given

6.4 g sample

Required

The empirical formula

Solution

mass C :

= 12/44 x 8.37 g

= 2.28

mass H :

= 2/18 x 2.75 g

= 0.305

mass N = 1.06

mass S :

= 32/64 x 1.23

= 0.615

mass O = 6.4 - (2.28+0.305+1.06+0.615) = 2.14 g

Mol ratio :

= C : H : N : S : O

= 2.28/12 : 0.305/1 : 1.06/14 : 0.615/32 : 2.14/16

= 0.19 : 0.305 : 0.076 : 0.019 : 0.133 divided by 0.019

= 10 : 16 : 4 : 1 : 7

The empirical formula :

C₁₀H₁₆N₄SO₇

3 0
3 years ago
Of the following: H2(g); He(g); CO2(g); which would behave least like an ideal gas? Why?
Margarita [4]
Answer:

CO2(g)

Because CO2 is the larges molecule with specific geometric, therefore it is not likely to behave as an ideal gas.
4 0
3 years ago
Mass of a mole is known as
gayaneshka [121]

Answer:

Molar mass is the mass of a given substance divided by the amount of that substance, measured in g/mol. For example, the atomic mass of titanium is 47.88 amu or 47.88 g/mol. In 47.88 grams of titanium, there is one mole, or 6.022 x 1023 titanium atoms.

Explanation:

Could I have branliest , heart, and 5 stars

Thanks!

7 0
2 years ago
Write a balanced equation for the complete combustion of propane, C3H8 . Do not enter phase symbols. Enter the alkane formula as
Anastaziya [24]
Answer:

C3H8 + 5O2 => 3CO2 + 4H2O

Explanation:

Hydrocarbon combustion is the reaction between a hydrocarbon and O2 producing CO2 and water.

C3H8 + O2 => CO2 + H2O

First we balance the C and H.

C3H8 + O2 => 3CO2 + 4H2O

Now we balance O for the answer!

C3H8 + 5O2 => 3CO2 + 4H2O

3 0
3 years ago
Be sure to answer all parts. treatment of (hoch2ch2ch2ch2)2co with acid forms a product of molecular formula c9h16o2 and a molec
liubo4ka [24]
The reaction described above is the formation of an acetal. The initial starting material has a central carbonyl and two terminal alcohol functional groups. In the presence of acid, the carbonyl will become protonated, making the carbon of the carbonyl susceptible to nucleophilic attack from one of the alcohols. The alcohol substitutes onto the carbon of the carbonyl to provide us with the intermediate shown.

The intermediate will continue to react in the presence of acid and the -OH that was once the carbonyl will become protonated, turning it into a good leaving group. The protonated alcohol leaves and is substituted by the other terminal alcohol to give the final acetal product. The end result of the overall reaction is the loss of water from the original molecule to give the spiroacetal shown in the image provided.

5 0
3 years ago
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