1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
emmainna [20.7K]
2 years ago
9

A solution of which of the following coordination compounds will form a precipitate when treated with aqueous AgNO3?

Chemistry
1 answer:
lidiya [134]2 years ago
3 0

Answer:

[Cr(NH3)6.]C13

Explanation:

Alfred Werner's coordination theory (1893) recognized two kinds of valency;

Primary valency which are nondirectional and secondary valency which are directional.

Hence, the number of counter ions precipitated from a complex depends on the primary valency of the central metal ion in the complex.

We must note that it is only these counter ions that occur outside the coordination sphere that can be precipitated by AgNO3.

If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.

You might be interested in
2NO(g) N2(g) + O2(g); Keq = 2.1 × 1030 What does the value of the equilibrium constant indicate?
olga_2 [115]
The equilibrium constant is a value which represents the equilibrium of a reaction. It is a reaction quotient when the reaction reached equilibrium. If Keq is greater than 1, the mixture contains mostly the products. On the other hand, if Keq is less than 1, the mixture contains the reactants. For this case, the mixture contains mostly products.
7 0
3 years ago
The formula of heavy water​
Crazy boy [7]

the formula of the heavy water is D2O

8 0
2 years ago
Reacting 35.4 ml of 0.220 m agno3 with 52.0 ml of 0.420 m k2cro4 results in what mass of solid formed
laila [671]
Answer is: 1.29 grams <span>of solid formed.
</span>Chemical reaction: 2AgNO₃(aq) + K₂CrO₄(aq) → Ag₂CrO₄(s) + 2KNO₃(aq).
n(AgNO₃) = c(AgNO₃) · V(AgNO₃).
n(AgNO₃) = 0.220 M · 0.0351 L.
n(AgNO₃) = 0.0078 mol; limiting reactant.
n(K₂CrO₄) = 0.420 M · 0.052 L.
n(K₂CrO₄) = 0.022 mol.
From chemical reaction: n(AgNO₃) : n(Ag₂CrO₄) = 2 : 1.
n(Ag₂CrO₄) = 0.0078 mol ÷ 2.
n(Ag₂CrO₄) = 0.0039 mol.
m(Ag₂CrO₄) = 0.0039 mol · 331.73 g/mol.
m(Ag₂CrO₄) = 1.29 g.

7 0
2 years ago
Determine the molarity for each of the following solutions A. 1.8×10^4mg of HCL in 0.075L of solutions
Goryan [66]
The answer would have to be a
4 0
2 years ago
Which type of bond, geometry and polarity of copper sulphate II ?​
ElenaW [278]
<h3>Sulfate takes two Copper atoms and gains negative valence charge,whereas the Copper gains a positive valence charge.The Sulfate is bonded in covalent bonds of polarity, Oxygen having the higher electronegativity, and therefore pulling the electrons closer to it's nucleus than to Sulfur's nucleus.</h3>

6 0
2 years ago
Other questions:
  • An element has atomic number 10 and an atomic mass of 20. How many neutrons are in the atom of this element? A. 10 B. 20 C. 30 D
    10·1 answer
  • Câu 1: Trong phân tử este (X) no, đơn chức, mạch hở có thành phần oxi chiếm 36,36 % khối lượng. Số đồng phân bố
    13·1 answer
  • A sample of gas has a volume of 5.58 l at a pressure of 715 mm hg. what is the volume of the gas when the pressure of the gas is
    7·1 answer
  • How are waves reflected, absorbed, or transmitted through materials such as air?
    13·1 answer
  • what is the best course of action if solid material remains in the flask after the heating step of recrystallization
    7·1 answer
  • Identify each of the following sets of quantum numbers as allowed or not allowed in the hydrogen atom.
    12·1 answer
  • 2C2H6 + 8O2 = 4CO2 + 6H2O
    6·1 answer
  • Neutrons are very important to an atom's ________<br> properties
    15·1 answer
  • What chemical compound is produced as a result of photosynthesis?<br> a
    7·2 answers
  • How many moles of na contain 7.88x1021 atoms of na
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!