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1 year ago

there are two types of waves: electromagnetic and mechanical. can either type travel regardless of the presence of a medium?

Physics

1 answer:

Dmitry_Shevchenko [17]1 year ago

3 0

Yes, electromagnetic can travel without medium.

Mechanical waves and electromagnetic waves are two important ways that energy is transported in the world around us.

Waves in water and sound waves in air are two examples of mechanical waves.

Mechanical waves are caused by a disturbance or vibration in matter, whether solid, gas, liquid, or plasma.

Matter that waves are traveling through is called a medium.

These mechanical waves travel through a medium by causing the molecules to bump into each other, like falling dominoes transferring energy from one to the next.

Sound waves cannot travel in the vacuum of space because there is no medium to transmit these mechanical waves.

On the other hand electromagnetic waves don't require medium for its propagation.

An easy example would be light which is an EM wave reaches earth even though space has no medium.

Learn more about different types of waves here:

brainly.com/question/13364787

#SPJ4

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A truck traveling with an initial velocity of 22m/s comes to a stop in 17.32 secs. What is the acceleration of the truck?

Tomtit [17]

Explanation:

Given:

v₀ = 22 m/s

v = 0 m/s

t = 17.32 s

Find: a

v = at + v₀

(0 m/s) = a (17.32 s) + (22 m/s)

a = -1.270 m/s²

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6 0

2 years ago

Read 2 more answers

Which of the following is not a use of electromagnetic waves? a night-vision bremote controls c x-rays d all are used of electro

sergey [27]

Use of electromagnetic because it moves very faster than others for example xrays theynar very very slow so that not It it is d.

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3 years ago

Which strategy should you use if your research question is too broad for the scope of your project? (1 O narrow the focus of res

Nesterboy [21]

Answer:

"Narrow the focus of research question"

Explanation:

O Narrow the focus of research question

This is good! You can still use your question, but focus in on something so you have a proper research project.

O Add another research question

Would adding another question to an already broad question help? No.

O Use the very first source you find for your project

If your question is too broad, you should not use whatever you see first as it may be incorrect or does not answer the question

O Change the scope of your project

You could, but if you have a set scope for your project (a) you might not be able to change it (b) you don't need to restart

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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2 years ago

A ball is thrown horizontally from the top of a building 37.5 m high. The ball strikes the ground at a point 80.3 m from the bas

trasher [3.6K]

Answer:

t = 2.77 s

Explanation:

The ball in its movement describes a curved line called a semiparabola, therefore two coordinates are required to fix the position at each instant of time, since the movement is performed in the X-Y plane:

Equation of movement of the ball in the X axis

X = v₀x*t Equation (1)

Equation of movement of the ball in the Y axis

Y = y₀+ v₀y*t -½ g*t² Equation (2)

Where

X : horizontal position in meters (m)

Y : vertical position in meters (m)

y₀ : initial vertical position in meters (m)

v₀x : X-initial speed in m/s

v₀y : Y-initial speed in m/s

g: acceleration due to gravity in m/s²

t : time to position (X,Y)

Data

y₀ = 37.5 m

v₀y = 0

g = 9.8 m/s²

Problem development

The time the ball remains in the air is the same as the ball takes to touch the floor, that is, Y = 0

We apply the Equation (2):

Y = y₀+ (v₀y)*t - (½) g*t²

0 = 37.5 +(0)*t- (1/2)*(g)*t²

0 = 37.5 - (1/2)*(9.8)*t²

(1/2)*(9.8)*t² = 37.5

t² = (2)(37.5)/(9.8)

$t= \sqrt{\frac{2*37.5}{9.8} }$

t = 2.77 s

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3 years ago

After driving a portion of the route, the taptap is fully loaded with a total of 26 people including the driver, with an average

Svet_ta [14]

Answer:

0.44807175m

Explanation:

k = Spring constant = $4\times 10^{4}\ N/m$ (Assumed, as it is not given)

g = Acceleration due to gravity = 9.81 m/s²

Total mass is

$m=26\times 67+3\times 15+5\times 3+25\\\Rightarrow m=1827\ kg$

The total weight will balance the spring force

$mg=kx\\\Rightarrow x=\dfrac{mg}{k}\\\Rightarrow x=\dfrac{1827\times 9.81}{4\times 10^{4}}\\\Rightarrow x=0.44807175\ m$

The springs are compressed by 0.44807175m

5 0

3 years ago