Answer: Option (A) and (D) are the correct statements.
Explanation:
Potential energy is defined as the energy obtained by an object due to its position. Whereas kinetic energy is defined as the energy obtained by an object due to the motion of its molecules.
When there will be only one phase present then addition or removal of energy will lead to change in kinetic energy of the substance but no change in potential energy will take place.
Whereas if change in phase is occurring then adding or removing any energy will lead to change in potential energy of the substance while kinetic energy will remain the same.
Thus, we can conclude that correct statements are as follows.
- While only one phase is present, adding or removing energy changes PE but not KE.
- During a phase change, adding or removing energy changes PE but not KE.
Can someone pls help us with this question I need the answer too
We know that the formula for static friction is:
Fs = μ N
where,
μ is the coefficient of static friction = 0.180
N is the normal force = weight of the cup = m g
We also know that from the Newton’s second law of motion,
the formula for net force is:
Fnet = m a
where m is the mass of the cup and a is the acceleration
of the cup
To prevent the cup from sliding backward, the static
friction Fs must cancel out the net Force Fnet, that is:
Fnet – Fs = 0
Therefore:
m a – μ N = 0
m a = μ N
m a = μ (m g)
Cancelling m:
a = μ g
a = 0.180 (9.81 m / s^2)
a = 1.7658 m / s^2
Therefore the plane can only have an acceleration of
about 1.77 m/s^2 before the cup starts to slide.
Answer:
f = 5.3 Hz
Explanation:
To solve this problem, let's find the equation that describes the process, using Newton's second law
∑ F = ma
where the acceleration is
a =
B- W = m \frac{d^2 y}{dt^2 }
To solve this problem we create a change in the reference system, we place the zero at the equilibrium point
B = W
In this frame of reference, the variable y' when it is oscillating is positive and negative, therefore Newton's equation remains
B’= m
the thrust is given by the Archimedes relation
B = ρ_liquid g V_liquid
the volume is
V = π r² y'
we substitute
- ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }
this differential equation has a solution of type
y = A cos (wt + Ф)
where
w² = ρ_liquid g π r² /m
angular velocity and frequency are related
w = 2π f
we substitute
4π² f² = ρ_liquid g π r² / m
f =
calculate
f =
f = 5.3 Hz
Answer:
<h3>I think this will answer your question. This is information is not mine and this rightfully belongs to <u>columbia.edu.</u></h3><h3><u /></h3>
This brightly colored fish is native to the Indo-Pacific from Australia north to southern Japan and south to Micronesia. The lionfish is usually found in coral reefs of tropical waters, hovering in caves or near crevices. Native regions as well as Savannah, Georgia; Palm Beach and Boca Raton, Florida; Long Island, New York; Bermuda and possibly Charleston. In southern Florida and off the coast of the Carolinas in early to mid 1990s.
<h3><u /></h3>