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Anvisha [2.4K]
3 years ago
6

A truck slows down. Which claim about the forces acting on the truck must be true? Choose 1 answer: Choose 1 answer: (Choice A)

A There are no forces on the truck. (Choice B) B There is no net force on the truck. (Choice C) C There is not enough information. (Choice D) D There is a net force on the truck.
Physics
1 answer:
Pie3 years ago
4 0

Answer:

"There is a net force on the truck" is true about the forces acting on the truck.

Explanation:

When truck is in contact with the road and is moving, several forces acts on the moving truck.

The net force is a sum of the forces that acts in opposite directions and same directions. When the truck is moving there is a normal force of the road acting upwards which is balanced by the weight of the truck that acts downward.

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efficiancy=40 percent

Explanation:

efficiency=energy output/energy input×100

efficiancy=8J/20J×100

efficiancy=0.4×100

efficiancy=40 percent

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The owners want the speed at the bottom of the first hill doubled. How much higher must the first hill be built?
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3 years ago
Most of our Solar system is composed of___
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Answer:

empty space

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5 0
2 years ago
Two loudspeakers in a 20c room emit 686 hz sound waves along the x-axis.a. if the speakers are in phase, what is the smallest di
jeyben [28]

<u>Answer :</u>

(a) d = 0.25 m

(b) d = 0.5 m

<u>Explanation :</u>

It is given that,

Frequency of sound waves, f = 686 Hz

Speed of sound wave at 20^0\ C is, v = 343 m/s

(1) Perfectly destructive interference occurs when the path difference is half integral multiple of wavelength i.e.

d=\dfrac{\lambda}{2}........(1)

Velocity of sound wave is given by :

v=f\times \lambda

d=\dfrac{v}{2f}

d=\dfrac{343\ m/s}{2\times 686\ Hz}

d=0.25\ m

Hence, when the speakers are in phase the smallest distance between the speakers for which the interference of the sound waves is perfectly destructive is 0.25 m.

(2) For constructive interference, the path difference is integral multiple of wavelengths i.e.

d=n\lambda  ( n = integers )

Let n = 1

So, d=\dfrac{v}{f}

d=\dfrac{343\ m/s}{686\ Hz}

d=0.5\ m

Hence, the smallest distance between the speakers for which the interference of the sound waves is maximum constructive is 0.5 m.

4 0
3 years ago
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