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Anvisha [2.4K]
4 years ago
6

A truck slows down. Which claim about the forces acting on the truck must be true? Choose 1 answer: Choose 1 answer: (Choice A)

A There are no forces on the truck. (Choice B) B There is no net force on the truck. (Choice C) C There is not enough information. (Choice D) D There is a net force on the truck.
Physics
1 answer:
Pie4 years ago
4 0

Answer:

"There is a net force on the truck" is true about the forces acting on the truck.

Explanation:

When truck is in contact with the road and is moving, several forces acts on the moving truck.

The net force is a sum of the forces that acts in opposite directions and same directions. When the truck is moving there is a normal force of the road acting upwards which is balanced by the weight of the truck that acts downward.

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Respuesta:

24m

Explicación:

Según la ecuación de movimiento

v = u + en

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tiempo t = 4s

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12 = 0 + 4a

a = 12/4

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Lo siguiente es obtener la distancia;

S = ut + 1 / 2at²

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3 years ago
A rotating wheel requires 5 s to rotate 38 revolutions. Its angular velocity at end of time interval 5-s is 79 rad/s. What is th
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"Rotating wheel" is meant to indcate that the wheel is already rotating at the start. Denote the initial angular velocity by <em>ω₀</em>. Then the angular displacement <em>θ</em> at time <em>t</em> is

<em>θ</em> = <em>ω₀t</em> + 1/2 <em>αt</em> ²

while the angular velocity <em>ω</em> is

<em>ω</em> = <em>ω₀</em> + <em>αt</em>

<em />

It takes 5 s for the wheel to rotate 38 times, or turn a total of (2<em>π</em> rad/rev) (38 rev) = 76<em>π</em> rad, as well as to reach an angular velocity of 79 rad/s, so that

76<em>π</em> rad = <em>ω₀</em> (5 s) + 1/2 <em>α</em> (5 s)²

79 rad/s = <em>ω₀</em> + <em>α</em> (5 s)

Solve the second equation for <em>ω₀</em> and substitute into the first equation, then solve for <em>α</em> :

<em>ω₀</em> = 79 rad/s - <em>α</em> (5 s)

==>   76<em>π</em> rad = (79 rad/s - <em>α</em> (5 s)) (5 s) + 1/2 <em>α</em> (5 s)²

==>   76<em>π</em> rad = (79 rad/s) (5 s) - 1/2 <em>α</em> (5 s)²

==>   1/2 <em>α</em> (5 s)² = (79 rad/s) (5 s) - 76<em>π</em> rad

==>   <em>α</em> = ((79 rad/s) (5 s) - 76<em>π</em> rad) / (1/2 (5 s)²)

==>   <em>α</em> ≈ 12.5 rad/s²

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