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FinnZ [79.3K]
3 years ago
5

If 71.5 moles of an ideal gas is at 5.03 atm at 6.80 °C, what is the volume of the gas?

Chemistry
1 answer:
meriva3 years ago
5 0
Use the clapeyron equation:

T in kelvin : 6.80 + 273 => 279.8 K

R = 0.082 

n = 71.5 moles

P = 5.03 atm

Therefore:

P x V = n x R x T

5.03 x V = 71.5 x 0.082 x 279.8

5.03 x V = 1640.4674

V = 1640.4674 / 5.03

V = 326.13 L

hope ths helps!
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<h3><u>Answer;</u></h3>

Empirical formula = C₂H₃O

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<h3><u>Explanation</u>;</h3>

Empirical formula

Moles of;

Carbon = 55.8 /12 = 4.65 moles

Hydrogen = 7.04/ 1 = 7.04 moles

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4.65/2.3225 = 2.0

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Therefore;

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43n = 301.35

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Molecular formula = (C2H3O)7

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