Answer:
7.65 moles of silver are produced
Explanation:
Zinc, Zn, reacts with silver nitrate, AgNO3, as follows:
Zn + 2AgNO3 → Zn(NO3)2 + 2Ag
<em>Where 1 mole of Zn reacts with an excess of AgNO3 to produce 2 moles of Ag</em>
To solve this question we must convert the mass of Zn to moles and, using the chemical equation, we can find the moles of Ag as follows:
<em>Moles Zn (Molar mass: 65.38g/mol):</em>
250g Zn * (1mol / 65.38g) = 3.824 moles Zn
<em>Moles Ag:</em>
3.824 moles Zn * (2mol Ag / 1mol Zn) =
<h3>7.65 moles of silver are produced</h3>
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Answer:
<h3>601.93 g/mol</h3>
<h3>explanation:</h3>
Problem: The Ba3(PO4)2 (molar mass = 601.93 g/mol) precipitate that formed from a salt mixture has a mass of 0.667 g.
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