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3 years ago

Confirmatory test of oxygen meaning?

Chemistry

1 answer:

Darya [45]3 years ago

4 0

Answer:

Oxygen supports combustion so a good method of testing for oxygen is to take a glowing splint and place it in a sample of gas, if it re-ignites the gas is oxygen. This is a simple but effective test for oxygen.

Explanation:

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Given that the density of water is 0.975 g/mL and that 171 g of sucrose (molar mass: 342.30 g/mol) is dissolved in 512.85 mL of

nikitadnepr [17]

1.00 m is the molality of this solution

7 0

3 years ago

Read 2 more answers

The following is an example of which type of chemical reaction?AgNO3 (aq) + NaCl (aq) --> AgCl (s) + NaNO3 (aq)

OLEGan [10]

Notice that the metals trade places. That means it is a double replacement RXN or C

4 0

3 years ago

Select the correct answer. If the EMF produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of s

serious [3.7K]

Given:

EMF = 0.88 V

Strength of magnetic field, B = 0.075 N/A-m

Velocity, v = 4.20 m/s

To determine:

The length of wire, L

Explanation:

The EMF is related to strength of the magnetic field B as:

EMF = L*B*v

L = EMF/B*v = 0.88/0.075*4.20 = 2.79 m

Ans: The length of the wire is around 2.8 m

3 0

3 years ago

. KMnO4 oxidizes ethyl benzene to benzoic acid. If this reaction generally results in a 40 % experimental yield, how many grams

lyudmila [28]

Answer:

530.835 g

Explanation:

First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:

244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acid

Theoretically, one mol of ethyl benzene would produce one mol of benzoic acid. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.

With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:

2.00 moles benzoic acid * $\frac{1molEthylBenzene}{0.4molBenzoicAcid}$ = 5.00 moles ethyl benzene

Finally we convert moles of ethyl benzene (C₈H₁₀) into grams, using its molar mass:

5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzene

7 0

3 years ago

The intensity of illumination at any point from a light source is proportional to the square of the reciprocal of the distance b

SSSSS [86.1K]

Answer:

the stronger light 5.5 m apart from the total illumination

Explanation:

From the problem's statement , the following equation can be deducted:

I= k/r²

where I = intensity of illumination , r= distance between the point and the light source , k = constant of proportionality

denoting 1 as the stronger light and 2 as the weaker light

I₁= k/r₁²

I₂= k/r₂²

dividing both equations

I₂/I₁ = r₁²/r₂²=(r₁/r₂)²

solving for r₁

r₁ = r₂ * √(I₂/I₁)

since we are on the line between the two light sources , the distance from the light source to the weaker light is he distance from the light source to the stronger light + distance between the lights . Thus

r₂ = r₁ + d

then

r₁ = (r₁ + d)* √(I₂/I₁)

r₁ = r₁*√(I₂/I₁) + d*√(I₂/I₁)

r₁*(1-√(I₂/I₁)) = d*√(I₂/I₁)

r₁ = d*√(I₂/I₁)/(1-√(I₂/I₁)) =

r₁ = d/[√(I₁/I₂)-1)]

since the stronger light is 9 times more intense than the weaker

I₁= 9*I₂ → I₁/I₂ = 9 →√(I₁/I₂)= 3

then since d=11 m

r₁ = d/[√(I₁/I₂)-1)] = 11 m / (3-1) = 5.5 m

r₁ = 5.5 m

therefore the stronger light 5.5 m apart from the total illumination

5 0

3 years ago