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3 years ago

Why is Cu+O=2CuO unbalanced

2 answers:

6 0

Because the two before the cuo means there is 2 moles of each atom and in the reactants there is only one mole of each so to balance the equation u need to put 2 before the cu and before the o

stepan [7]3 years ago

3 0

Answer:

because the product of CuO contains 2 molecules so it is unbalanced

Explanation:

to balance it 2Cu+2O=4CuO now it is balanced

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What does MVLMEN stand for

Soloha48 [4]

There are a couple things that this can stand for

3 0

3 years ago

The following are electronegativity. What value should be where the M is?0.981.57M2.553.043.443.98No data

ipn [44]

Answer 2.04

Explanation

Electronegativity decreases down the group and increases across the period in the periodic table.

In the period two of the periodic table,we have the following values for electronegativities with respect to its elements.

Li...........0.98

Be.........1.57

B..........2.04

C.........2.55

N..........3.04

O...........3.44

F...........3.98

Ne........n.a

The value that should be where M is is 2.04

6 0

1 year ago

In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) ⇌

Oksana_A [137]

Answer: Equilibrium constant is 0.70.

Explanation:

Initial moles of $CO$ = 0.35 mole

Volume of container = 1 L

Initial concentration of $CO=\frac{moles}{volume}=\frac{0.35moles}{1L}=0.35M$

Initial moles of $H_2O$ = 0.40 mole

Volume of container = 1 L

Initial concentration of $H_2O=\frac{moles}{volume}=\frac{0.40moles}{1L}=0.40M$

equilibrium concentration of $CO=\frac{moles}{volume}=\frac{0.18moles}{1L}=0.18M$ [/tex]

The given balanced equilibrium reaction is,

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

Initial conc. 0.35 M 0.40M 0 0

At eqm. conc. (0.35-x) M (0.40-x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CO_2]\times [H_2O]}{[CO]\times [H_2O]}$

$K_c=\frac{x\times x}{(0.40-x)(0.35-x)}$

we are given : (0.35-x)= 0.18

x = 0.17

Now put all the given values in this expression, we get :

$K_c=\frac{0.17\times 0.17}{(0.40-0.17)(0.35-0.17)}$

$K_c=0.70$

Thus the value of the equilibrium constant is 0.70.

5 0

3 years ago

I will give the first person brainliest! please helppp

Murrr4er [49]

okay so the Answer is c

7 0

3 years ago

Based on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the expe

Anika [276]

Factors that increases reaction rate such as increase in concentration or pressure will reduce reaction time whereas factors that decrease reaction rate such as inhibitors will increase reaction time.

<h3>What are the factors that affect reaction rate?</h3>

Factors that affect reaction rate are those factors which increase or decrease the rate of chemical reaction.

The factors that affect reaction rate include:

temperature
concentration/pressure
catalysts
surface area
nature of substance

Any factor that increases reaction rate such as increase in concentration or pressure will reduce reaction time whereas factors that decrease reaction rate such as inhibitors will increase reaction time.

Learn more about factors affecting reaction rate at: brainly.com/question/14817541

#SPJ1

6 0

2 years ago

Why is Cu+O=2CuO unbalanced ​

Why is Cu+O=2CuO unbalanced