Hey the answer to the question is
m = 0.40
Let N be the normal force that forces the person against the wall.
Then u N = m g is the frictional force supporting the person's weight
and N = m g / u
also, N = m v^2 / R is the normal force providing the centripetal acceleration
So, m g / u = m v^2 / R
v^2 = g R / u
since v = 2 pi R T
4 pi^2 R^2 T^2 = g R / u and T^2 = g / (4 u pi^2 R)
T = 1/ (2 pi) (g /(u R))^1/2 = .159 * (9.8 m/s^2 / (.521 * 4.4 m)) ^1/2
T = .68 / s
Do you see any thing wrong here?
T should have units of seconds not 1 / seconds
v should be 2 * pi * R / T where T is the time for 1 revolution
So you need to make that correction in the above formula for v.
Answer:
The resulting force on the child is 3000 lbf
Explanation:
To find the force that acts on a child of 50 lb with a deceleration of 60 g's, we can use the formula:
Force = mass * acceleration
To find the force in lbf, we need to use the mass in lb and the acceleration in g (standard unit of gravity).
So we have that:
Force = 50 * 60
Force = 3000 lbf
So the resulting force on the child is 3000 lbf.
Answer:
hmm sorry but ill answer it later
Explanation:
