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dedylja [7]
2 years ago
11

If the mass of the earth and all objects on it were suddenly doubled, but the size remained the same, the acceleration due to gr

avity at the surface would become.
Physics
1 answer:
timofeeve [1]2 years ago
7 0

When the mass of Earth doubles, acceleration due to gravity doubles as well.

<h3>Acceleration due to gravity</h3>

Apply Newton's second law of motion;

F = mg --- (1)

where;

  • m is mass of the object
  • g is acceleration due to gravity

F = GmM/R²  --- (2)

where;

  • M is mass of Earth
  • R is radius of Earth

Solve (1) and (2)

mg =  GmM/R²

g = GM/R²

when the mass of Earth doubles, acceleration due to gravity becomes;

g' = G(2M)/R²

g' = 2(GM/R²)

g' = 2g

Thus, when the mass of Earth doubles, acceleration due to gravity doubles as well.

Learn more about acceleration due to gravity here: brainly.com/question/88039

#SPJ1

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3 years ago
9. An object starting with a velocity of 20m/s accelerates to
Aliun [14]

Answer:

6.25 s

Explanation:

V=u+at

t= (v-u)/a

 = (45-20)/4 = 6.25 s

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Finish the sentence below with the word that makes the sentence true.
Keith_Richards [23]

Answer:

Animals must eat other plants or animals to obtain the <u>energy</u> stored in the food

Explanation:

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<u>Animals -heterotrophes- are unable to process their own nutrients</u>, so they must obtain them from other organisms, either plants or animals. External food sources provide them with nutrients, which contain the energy substrate needed to perform their vital functions.

Learn more:

Autotrophs and heterotrophs brainly.com/question/7695115

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3 years ago
The liquid contained in batteries that conducts electric charge is called the: solution, electrolyte, suspension, colloid
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A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 9.00 mm and dielectric constant
PIT_PIT [208]

Answer:

9.96\cdot 10^{-10}J

Explanation:

The capacitance of the parallel-plate capacitor is given by

C=\epsilon_0 k \frac{A}{d}

where

ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity

k = 3.00 is the dielectric constant

A=30.0 cm^2 = 30.0\cdot 10^{-4}m^2 is the area of the plates

d = 9.00 mm = 0.009 m is the separation between the plates

Substituting,

C=(8.85\cdot 10^{-12}F/m)(3.00 ) \frac{30.0\cdot 10^{-4} m^2}{0.009 m}=8.85\cdot 10^{-12} F

Now we can calculate the energy of the capacitor, given by:

U=\frac{1}{2}CV^2

where

C is the capacitance

V = 15.0 V is the potential difference

Substituting,

U=\frac{1}{2}(8.85\cdot 10^{-12}F)(15.0 V)^2=9.96\cdot 10^{-10}J

4 0
3 years ago
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