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Nady [450]
1 year ago
7

The clearance of pus, cellular debris, dead neutrophils, and damaged tissue after inflammation is performed by:_________

Biology
1 answer:
yKpoI14uk [10]1 year ago
3 0

Macrophages are immune cells which are responsible for performing the functions like clearance of pus, cellular debris, dead neutrophils as well as damaged tissue after the inflammation has been performed.

Macrophages are a type of immune cells. They are large phagocytic cells which can be found either mobile as a white blood cell or they can also be found in a stationary form in the tissues. They can especially be found at the site of infection.

During inflammation, they enter about 72 hours post the initial response to perform the function of cleaning up the debris, pus and also the dead neutrophils.

To learn more about macrophages here

brainly.com/question/13260225

#SPJ4

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Explanation:

The sun protection factor is a comparison between the length of time it will take for a skin that has no sunscreen to begin reddening compared to a skin with sunscreen applied. Therefore, the ratings is an indication of the length of time a person will be protected from ultraviolet rays than when the individual has no sunscreen applied.

While higher SPF's are believed to offer more protection against UV rays, the added protection is usually just a negligible amount. They are very important for the skin and protect the body against diseases like cancer.

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Rhizoids are the _____ of bryophytes.<br> stems<br> roots<br> leaves<br> gametes
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There is more oxygen in the ............. than in the blood flowing through the​
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7 0
2 years ago
Is every human body built exactly the same anatomically?.
bekas [8.4K]

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4 0
2 years ago
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

6 0
3 years ago
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