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skelet666 [1.2K]
1 year ago
6

One mole of any substance contains 6.022 × 1023 representative particles (atoms, molecules, ions, or formula units). A sample of

silver metal consists of 4.26 nanomoles. How many silver atoms does it contain?
Chemistry
1 answer:
Nutka1998 [239]1 year ago
3 0

Answer:

it contains 2.56 x 10^15.

Explanation:

given no. of moles = 4.26 x 10^-9 atoms

one mole has 6.022 x 10^23 atoms

so it contains 4.26 x 10^-9 x 6.022 x 10^23 atoms

(If we suppose silver's atomic weight as 108.)

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Draw the ground-state electronic configuration for Mg.
vichka [17]

Answer:

(Ne)3s2

Explanation:

6 0
3 years ago
What is the balanced equation for the complete combustion of pentane (C5H12)?
LekaFEV [45]
2C5H12 + 16O2 —> 10CO2 + 12H2O

2•5=10 C 10=1•10
2•12=24 H 24=2•12
16•2=32 O 32=(10•2)+(1•12)
=20+12
6 0
4 years ago
Explain, in terms of intermolecular forces, why ammonia has a higher boiling point than the other compounds in the ta
Kobotan [32]
Answer is: ammonia has a higher boiling point because it has stronger intermolecular forces.

Intermolecular forces<span> are the forces between </span><span>molecules. The stronger are intermolecular forces, the higher is boiling point of compound, because more energy is needed to break interaction between molecules.
</span>There are several types of intermolecular forces: hydrogen bonding, i<span>on-induced dipole forces, ion-dipole forces andvan der Waals forces.</span>
7 0
3 years ago
When 5.00 g of NH4NO3 is dissolved in 100.0 g of water in a styrofoam cup, the T = - 3.82 ^°C. Is the process of dissolving ammo
miv72 [106K]

Answer:

The process is endothermic.

Heat is 26,9 kJ/mol

Explanation:

The dissolution of NH₄NO₃ in water is:

NH₄NO₃ → NH₄⁺ + NO₃⁻

As the change of temperature in the cup is ΔT = -3,82°C

<em>The process is endothermic</em>. Because the temperature is decreasing in the process. That means the process needs heat.

Assuming the  heat capacity of the solution is 4.18 J/Kg :

q = -C×m×ΔT

Where q is heat, C is heat capacity (4,18J/Kg), m is mass (105g) and ΔT is change in temperature (-3,82°C)

q = 1677 J ≈ <em><u>1,68kJ</u></em>

The moles of NH₄NO₃ dissolved are:

5,00g × (1mol / 80,043g) = <em><u>0,0625 moles</u></em>

That means heat of this process in kJ/ mol is:

1,68kJ / 0,0625moles = <em>26,9 kJ/mol</em>

<em />

I hope it helps!

8 0
3 years ago
The titration of 25.00 ml a 0.125 m hclo4 solution requires 27.07 ml of koh to reach the endpoint. what is the concentration of
agasfer [191]

Answer : The concentration of the KOH is, 0.115 M

Explanation :

Using dilution law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of an acid = 1

n_2 = acidity of a base = 1

M_1 = concentration of HClO_4 = 0.125 M

M_2 = concentration of KOH = ?

V_1 = volume of HClO_4 = 25 ml

V_2 = volume of NaOH = 27.07 ml

Now put all the given values in the above law, we get the concentration of the KOH.

1\times 0.125M\times 25ml=1\times M_2\times 27.07ml

M_2=0.115M

Therefore, the concentration of the KOH is, 0.115 M

5 0
4 years ago
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