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bekas [8.4K]
3 years ago
14

If a substance can be physically separated into its components, is it a pure substance or a mixture?

Chemistry
2 answers:
oee [108]3 years ago
5 0
It is a mixture .
A substance that can be physically separated into its compounds first need to get decomposed to get separated and is called a mixture...


100%sure answer...

HOPE IT HELPS YOU '_'
Marizza181 [45]3 years ago
4 0
I think its pure substance since you are breaking into its components. For example if you were to break the components of salt apart (NaCl) You will be left with sodium and chloride which are the pure elements of salt. Therefore i believe pure is the best answer.
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40. What is the mass of 3 moles of H 2 O
Leya [2.2K]

Answer:

54g

Explanation:

Given parameters:

Number of moles of H₂O  = 3 moles

Unknown:

mass of water  = ?

Solution:

To solve this problem, we use the expression below:

         mass  = number of moles x molar mass

Molar mass of H₂O  = 2(1)  + 16  = 18g/mol

Mass of water  = 3 x 18  = 54g

3 0
3 years ago
Calculate the volume of compound Y needed to make a 350 pg/ml treatment solution in 2 ml of 1x PBS using a stock solution contai
harina [27]

Answer:

14 mL

Explanation:

To prepare a solution by a concentrated solution, we must use the equation:

C1xV1 = C2xV2, where <em>C</em> is the concentration, <em>V</em> is the volume, 1 is the initial solution and 2 the final solution.

The final solution must have 2 mL and a concentration of 350 pg/mL, and the initial solution has a concentration of 50 pg/mL.

Then:

50xV1 = 350x2

50xV1 = 700

V1 = 700/50

V1 = 14 mL

4 0
3 years ago
A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0
3 years ago
815 yd to km (need 3 sig fig)
SpyIntel [72]

<u>Answer:</u> The correct answer is 0.745 km

<u>Explanation:</u>

We are given:

A numerical value of 815 yards

To convert this into kilometers, we use the conversion factor:

1 km = 1093.6 yards

Converting the given value into kilometers, we get:

\Rightarrow 815yd\times \frac{1km}{1093.6yd}=0.745km

Hence, the correct answer is 0.745 km

5 0
3 years ago
15 POINTS PLEASE HELP
Lapatulllka [165]

Answer:

Neutrons = ( Atomic mass – Atomic number ) ( A–Z )

Protons and Electrons are equal to the atomic number

For example Neon,

Mass number (A) = 20

Atomic Number (Z) = 10

Number of Protons = 10

Number of Electrons = 10

Number of Neutrons = ( A–Z ) = 10

Electronic distribution :

K= 2

L= 8

4 0
3 years ago
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