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Arada [10]
2 years ago
12

How many electrons in an atom can have the quantum number n equal to 2 and ml equal to 2?

Chemistry
1 answer:
disa [49]2 years ago
3 0

The number of electrons in an atom which has its quantum number n equal to 2 (n = 2) and ml equal to 2 (ml = 2) is equal to zero (0).

<h3>What is an electron?</h3>

An electron can be defined as a subatomic particle that is negatively charged and it's found outside the nucleus of the atom of a chemical element. This ultimately implies that, an electron is the opposite of a subatomic particle called proton.

<h3>What is the Pauli exclusion principle?</h3>

The Pauli exclusion principle can be defined as a principle which states that no two electrons (fermions) in a single atom can have the same numerical values for all four (4) of their electronic quantum numbers.

Furthermore, this principle states that the orbital of an atom can only contain a maximum of two (2) electrons, and they must have opposing spin orientations.

Based on Pauli exclusion principle, we can infer and logically deduce that the number of electrons in an atom which has its quantum number n equal to 2 (n = 2) and ml equal to 2 (ml = 2) would be equal to zero (0).

Read more on Pauli exclusion principle here: brainly.com/question/20564744

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Consider two concentric spheres whose radii differ by t = 1 nm, the "thickness" of the interface. At what radius (in nm) of sphe
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Radius of the interior sphere = 3.847 nm

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The volume of the shell (Vs) is equal to the difference of the volume of the outer sphere (Vo) and the volume of the inner sphere (Vi). Then:

V_s=V_o-V_i=V_i\\V_o=2*V_i\\

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\frac{4 \pi}{3}*r_o^{3}  = 2 * \frac{4 \pi}{3}*r_i^{3}  \\\\\frac{4 \pi}{3}*(r_i+e)^{3}  = 2 * \frac{4 \pi}{3}*r_i^{3}  \\\\(r_i+e)^{3}  = 2 *r_i^{3}  \\\\(r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3})=2r_i^{3}\\\\-r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3}=0\\\\-r_i^{3}+3r_i^{2}+3r_i+1=0

To find ri that satisfies this equation we have to find the roots of the polynomial.

Numerically, it could be calculated that ri=3.847 nm satisfies the equation.

So if the radius of the interior sphere is 3.847 nm, the volume of the interior sphere is equal to the volume of the shell of 1nm.

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