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vova2212 [387]
3 years ago
6

What is this answer to this problem

Chemistry
2 answers:
andrew11 [14]3 years ago
5 0

Answer:

gdhjvdhihfhddjcuh

dhsgbeyfgjgjjkk

tjfhh

gjgu

<h3 />
Novosadov [1.4K]3 years ago
3 0
The answer is 192, you just multiply the sides
You might be interested in
How many moles of \ce{CO2}COX
inn [45]

Answer:

4.5 moles of carbon dioxide

Explanation:

Given parameters:

Mass of CH₄   = 72g

Unknown:

number of moles of CO₂ produced  = ?

Solution:

To solve this problem, let us write the reaction equation first;

            CH₄     +    2O₂     →    CO₂    +   2H₂O

Now we know that O₂ is in excess and CH₄ is the limiting reactant that will determine the extent of the reaction.

Let us find the number of moles of   CH₄ ;

                Number of moles  = \frac{mass}{molar mass}

                                  molar mass of  CH₄ = 12 + 4  = 16g/mol

              Number of moles  = \frac{72}{16}   = 4.5moles

From the reaction equation;

                     1 mole of methane produced 1 mole of carbon dioxide

       4.5 moles of methane will produce 4.5 moles of carbon dioxide

6 0
4 years ago
A calibration curve was created to determine the quantity of protein in a solution. The calibration curve has the form of a stra
baherus [9]

Answer:

The solution has 11.4 μg protein

Explanation:

Hi there!

The corrected absorbance will be the measured absorbance minus the absorbance of the blank that is a solution without protein.

Then, the corrected absorbance will be:

0.276 - 0.061 = 0.215

Now, using the equation of the calibration curve, we can obtain the quantity of protein present in the solution:

0.215 = 0.0182x + 0.007

(0.215 - 0.007) / 0.0182 = x

x = 11.4 μg

The solution has 11.4 μg protein

7 0
3 years ago
With all the concerns associated with non-renewable resources, why
Alex Ar [27]

Answer:

2

Explanation:

I did this alderman

4 0
3 years ago
If the temperature of air in gabor's lungs is 37∘c (98.6∘f), and the volume is 6l, how many moles of air n must be released by t
umka21 [38]
Missing question:
Suppose Gabor, a scuba diver, is at a depth of 15 m. Assume that:
1. The air pressure in his air tract is the same as the net water pressure at this depth. This prevents water from coming in through his nose.
2. The temperature of the air is constant (body temperature).
3. The air acts as an ideal gas.
4. Salt water has an average density of around 1.03 g/cm^3, which translates to an increase in pressure of 1.00 atm for every 10.0 m of depth below the surface. Therefore, for example, at 10.0 m, the net pressure is 2.00 atm.

T = 37°C = 310 K.
p₁ = 2,5 atm = 253,313 kPa.
p₂ = 1 atm = 101,325 kPa.
Ideal gas law: p·V = n·R·T.
n₁ = 253,313 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₁ = 0,589 mol.
n₂ = 101,325 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₂ = 0,2356 mol.
Δn = 0,589 mol - 0,2356 mol = 0,3534 mol.
5 0
4 years ago
Will someone please help me with numbers 22-26? I would really appreciate it. Thank you.
Naddika [18.5K]
Do You Mean 22 - 26 = 4
5 0
4 years ago
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