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Wewaii [24]
3 years ago
8

A boat is traveling with a velocity of 18 meters/second relative to water and the river is flowing at a velocity of 2.5 meters/s

econd relative to the shore. What will be the velocity of the boat if the boat and the water are in opposite directions?
Physics
2 answers:
ddd [48]3 years ago
8 0
Vt = Vboat - Vriver 
Vt = 18 - 2.5 = 15.5 m/s 

If the boat's direction is the same as the water, you sum the velocities of the river and the boat . 
I am Lyosha [343]3 years ago
8 0

Answer:Velocity of boat is 15.5 \frac{m}{s}

Explanation:Using equation of relative motion

V_{boat,water}=V_{boat}-V{water}

=>V_{boat}=V_{boat,water}+V_{water}

where velocity of boat relative to water , V_{boat,water}=18 m/s

velocity of water, V_{water}=-2.5\frac{m}{s}

and velocity of boat , V_{boat}=? \frac{m}{s} to be calculated.

Putting the known values in the above equation , we get

V_{boat}= (18-2.5)\frac{m}{s}=15.5\frac{m}{s}

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A circular swimming pool has a diameter of 12 m. The circular side of the pool is 3 m high, and the depth of the water is 2.5 m.
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Answer:

Explanation:

Diameter of pool = 12 m

radius of pool, r = 6 m

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m = πr²h x d

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please help! find magnitude and direction (the counterclockwise angle with the +x axis) of a vector that is equal to a + c
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Answer:

Option (2)

Explanation:

From the figure attached,

Horizontal component, A_x=A\text{Sin}37

A_x=12[\text{Sin}(37)]

     = 7.22 m

Vertical component, A_y=A[\text{Cos}(37)]

    = 9.58 m

Similarly, Horizontal component of vector C,

C_x  = C[Cos(60)]

     = 6[Cos(60)]

     = \frac{6}{2}

     = 3 m

C_y=6[\text{Sin}(60)]

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R_x=7.22-3=4.22 m

R_y=9.58-5.20 = 4.38 m

Now magnitude of the resultant will be,

From ΔOBC,

R=\sqrt{(R_x)^{2}+(R_y)^2}

   = \sqrt{(4.22)^2+(4.38)^2}

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Direction of the resultant will be towards vector A.

tan(∠COB) = \frac{\text{CB}}{\text{OB}}

                  = \frac{R_y}{R_x}

                  = \frac{4.38}{4.22}

m∠COB = \text{tan}^{-1}(1.04)

             = 46°

Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.

Option (2) will be the answer.

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