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Wewaii [24]
3 years ago
8

A boat is traveling with a velocity of 18 meters/second relative to water and the river is flowing at a velocity of 2.5 meters/s

econd relative to the shore. What will be the velocity of the boat if the boat and the water are in opposite directions?
Physics
2 answers:
ddd [48]3 years ago
8 0
Vt = Vboat - Vriver 
Vt = 18 - 2.5 = 15.5 m/s 

If the boat's direction is the same as the water, you sum the velocities of the river and the boat . 
I am Lyosha [343]3 years ago
8 0

Answer:Velocity of boat is 15.5 \frac{m}{s}

Explanation:Using equation of relative motion

V_{boat,water}=V_{boat}-V{water}

=>V_{boat}=V_{boat,water}+V_{water}

where velocity of boat relative to water , V_{boat,water}=18 m/s

velocity of water, V_{water}=-2.5\frac{m}{s}

and velocity of boat , V_{boat}=? \frac{m}{s} to be calculated.

Putting the known values in the above equation , we get

V_{boat}= (18-2.5)\frac{m}{s}=15.5\frac{m}{s}

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A uniform rod of length L rests on a frictionless horizontal surface. The rod pivots about a fixed frictionless axis at one end.
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A 41 kg girl and a 5.0 kg sled are on the frictionless ice of a frozen lake, 15 m apart but connected by a rope of negligible ma
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(a) 0.8 m/s^2

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F=ma

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According to Newton's third law (action-reaction law), since the girl exerts a force on the sled, then the sled exerts an equal and opposite force on the girl as well. This means that the force exerted on the girl is also F = 4.0 N. As before, we can calculate the acceleration of the girl by using Newton's second law:

F=ma

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Taking the initial position of the girl as x = 0, the position at time t of the girl is given by:

x(t)=\frac{1}{2}a_g t^2

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The sled starts instead its motion from x = 15 m, so its position at time t is given by

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