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2 years ago

What does a ‘0’ mean in binary code?

Physics

1 answer:

posledela2 years ago

6 0

Answer:

<em>The answer is C, a switch is set so an electrical charge cannot flow.</em>

Explanation:

In a transistor (working as a switch), 0 represents no flow of electricity; 1 represents electricity being allowed to flow

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Why did Copernicus want to develop a completely new system for predicting planetary positions? Provide two reasons.

LiRa [457]

Answer:

1) improve the quality of data

2) new system is more simple and elegant

Explanation:

the reason for being selected new system of determining planetary positions are

1) he want to improve the quality of data for having new planetary positioned value.

b) he believed that new system is more simple and elegant for determining planetary positions by both skilled and unskilled user i.e. astronomers and general public

7 0

3 years ago

An unusually high tide is called a _______ tide.

Monica [59]

Proxigean Spring <span>Tide</span>

8 0

2 years ago

A Blu-ray disk spins up from rest to an angular speed of about 10,000 revolutions per minute. If it

erma4kov [3.2K]

The correct answer is B 5,000 rev/s^2

4 0

2 years ago

Question 10 of 10Which statements are true?Check all that apply.O A. If heat is added to a substance, the temperature alwaysincr

inna [77]

The true statements are B and C.

This comes from the following facts:

Even when heat is added to a substance in a change of phase the temperature does not increases since this heat is latent heat.

3 0

1 year ago

The ratio of Earth's radius to that of Mars (RR/RM) is approximately 19/10, and the ratio of the density of Earth to that of Mar

drek231 [11]

Answer:

The answer is letter c.

Explanation:

We need to find the relation of masses first and then apply the equivalence principle.

We know that the ratio of the density of Earth to that of Mars is approximately 14/10.

$\frac{\rho_{E}}{\rho_{M}}=\frac{14}{10}$

Density is the mass divided by the volume (Here the volume of each planet is a solid sphere of uniform density), so

$\rho_{E}=\frac{M_{E}}{V_{E}}=\frac{M_{E}}{\frac{4}{3}\pi R_{E}^{3}}$

$\rho_{M}=\frac{M_{M}}{V_{M}}=\frac{M_{E}}{\frac{4}{3}\pi R_{M}^{3}}$

Then, the ratio between the densities will be:

$\frac{\rho_{E}}{\rho_{M}}=\frac{M_{E}R_{M}^{3}}{M_{M}R_{E}^{3}}=\frac{14}{10}$

We know that $\frac{R_{E}}{R_{M}}=19/10$ , then we can write the above equation as:

$\frac{M_{E}}{M_{M}}=\left(\frac{R_{E}}{R_{M}}\right)^{3} \frac{14}{10}$

$\frac{M_{E}}{M_{M}}=(\frac{19}{10})^{3} \frac{14}{10}$

Now, using the gravitational force:

To the earth

$g=G\frac{M_{E}}{R_{E}^{2}}$

To the mars

$g=G\frac{M_{M}}{R_{M}^{2}}$

But, we know that $M_{M}=(\frac{10}{19})^{3} \frac{10}{14}M_{E} \: and \: R_{M}=\frac{10}{19}R_{E}$

Therefore, we will have:

$g=G\frac{(\frac{10}{19})^{3} \frac{10}{14}M_{E}}{(\frac{10}{19}R_{E})^{2}}$

$g=\frac{10*10}{14*19}G\frac{M_{E}}{R_{E}^{2}}$

$g_{M}=0.38g$

$g_{M} \approx \frac{2}{5}g$

The answer is letter c.

I hope it helps you!

5 0

3 years ago