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Karo-lina-s [1.5K]
3 years ago
9

What does a ‘0’ mean in binary code?

Physics
1 answer:
posledela3 years ago
6 0

Answer:

<em>The answer is C, a switch is set so an electrical charge cannot flow.</em>

Explanation:

In a transistor (working as a switch), 0 represents no flow of electricity; 1 represents electricity being allowed to flow

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A spring stretches by 0.0177 m when a 2.82-kg object is suspended from its end. How much mass should be attached to this spring
Artemon [7]

The mass attached to the spring must be 0.72 kg

Explanation:

The frequency of vibration of a spring-mass system is given by:

f=\frac{1}{2\pi} \sqrt{\frac{k}{m}} (1)

where

k is the spring constant

m is the mass attached to the spring

We can find the spring constant by using Hookes' law:

F=kx

where

F is the force applied on the spring

x is the stretching of the spring

When a mass of m = 2.82 kg is applied to the spring, the force applied is the weight of the mass, so we have

mg=kx

and using g=9.8 m/s^2 and x=0.0177 m, we find

k=\frac{mg}{x}=\frac{(2.82)(9.8)}{0.0177}=1561.3 N/m

Now we want the frequency of vibration to be

f = 7.42 Hz

So we can rearrange eq.(1) to find the mass m that we need to attach to the spring:

m=\frac{k}{(2\pi f)^2}=\frac{1561.3}{(2\pi (7.42))^2}=0.72 kg

#LearnwithBrainly

6 0
3 years ago
A positively charged particle is moving toward the South in a region of space where there is a magnetic field directed down (tow
Alexxandr [17]

Answer:

F = Q V X B

V = south

B = down

V X B = east

8 0
2 years ago
Which of the following describes the number of times an analog wave is measured each second during an analog-to-digital conversi
noname [10]
C, conversion rate.
5 0
4 years ago
Explain how wind is the primary source for wave energy
siniylev [52]
Waves get their energy from the wind.
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3 years ago
Read 2 more answers
A 16.5-kg crate starts at rest at the top of a 60.0° incline. The coefficients of friction are μs = 0.400 and μk = 0.300. The cr
irga5000 [103]

Answer:

t = 1.62 s

Explanation:

given,

mass of the block m₁ = 16.5 Kg

m₂ = 8 Kg

angle of inclination = 60°

μs = 0.400 and μk = 0.300

time to slide 2 m = ?

a) let a is the acceleration of the block m₁ downward.

Net force acting on m₂,

F₂ = T - m₂ g

m₂a = T - m₂ g

a = \dfrac{T}{m_2} - g.......(1)

net force acting on m₁

F₁ = m₁g sin(60°) - μ_k m₁g cos (60°) - T

m₁ a = m₁g sin(60°) - μ_k m₁g cos (60°) - T

a = g sin(60^0) - \mu_k g cos (60^0) - \dfrac{T}{m_1}.........(2)

from equations 1 and 2

\dfrac{T}{m_2} - g = g sin(60^0) - \mu_k g cos (60^0) - \dfrac{T}{m_1}

\dfrac{T}{m_2} +\dfrac{T}{m_1} = g+ g sin(60^0) - \mu_k g cos (60^0)

 T\dfrac{m_1+m_2}{m_2\times m_1} = g+ g sin(60^0) - \mu_k g cos (60^0)

 T = \dfrac{g+ g sin(60^0) - \mu_k g cos (60^0)}{\dfrac{m_1+m_2}{m_2\times m_1}}

 T = {m_2\times m_1}\dfrac{g+ g sin(60^0) - \mu_k g cos (60^0)}{{m_1+m_2}}  

T = {16.5\times 8}\dfrac{9.8 + 9.8 sin(60^0) - 0.3\times 9.8 cos (60^0)}{{16.5+8}}

T = 90.61 N

from equation (1)

a = \dfrac{90.61}{8} - 9.8.......(1)

a = 1.52 m/s²

let t is the time taken

Apply,

d = ut + 0.5 a t²

2 = 0 + 0.5 x 1.52 x t²

t = \sqrt{2.63}

t = 1.62 s

5 0
3 years ago
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