Answer: 
Step-by-step explanation:
Given
Marcos purchased a sailboat for 
Each year the boat will decrease in value by 
After 1 year it is

after another year it becomes

After
years it is


Answer:
4x + 1 and 6x - 2x - 2 + 3
Step-by-step explanation:
we can expand and find 2 equations that are the same as this
one being 6x+3 -2x -2
and another being 4x + 1
hope this helps!
Answer:
q = log4 / log0.53
q = -2.189
Step-by-step explanation:
(0.53)^q = 4
Taking log of both sides!
q log 0.53 = log 4
q = log 4 / log 0.53
q = 0.602 / -0.275
q = - 2.189
This can be checked to confirm correctness.
Substituting q = -2.189
(0.53)^ -2.189 = 1/ 0.249
= 4.01 Proved!
(Note that the "1" is because of the negative sign)