Answer:
(A) -2940 J
(B) 392 J
(C) 212.33 N
Explanation:
mass of bear (m) = 25 kg
height of the pole (h) = 12 m
speed (v) = 5.6 m/s
acceleration due to gravity (g) = 9.8 m/s
(A) change in gravitational potential energy (ΔU) = mg(height at the bottom- height at the top)
height at the bottom = 0
= 25 x 9.8 x (0-12) = -2940 J
(B) kinetic energy of the Bear (KE) =
= = 392 J
(C) average frictional force =
- change in KE (ΔKE) = initial KE - final KE
- ΔKE = -
- when the Bear reaches the bottom of the pole, the final velocity (Vf) is 0, therefore the change in kinetic energy becomes ΔKE = - 0 = 392 J
\frac{-(ΔKE+ΔU)}{h}[/tex] =
= = 212.33 N
Answer:
Part a)
When rotated about the mid point
Part b)
When rotated about its one end
Explanation:
As we know that the angular acceleration of the rod is rate of change in angular speed
so we will have
Part a)
When rotated about the mid point
now torque is given as
Part b)
When rotated about its one end
now torque is given as
Answer:
115 km/h
Explanation:
= Mass of car A = 690 kg
= Mass of car B = 520 kg
g = Acceleration due to gravity = 9.81 m/s²
a = Acceleration
u = Initial velocity
v = Final velocity
Converting to km/h
Initial velocity of car A = 115 km/h
Answer:
or
23.4843749996 m
Yes
Explanation:
E = Electric field =
c = Speed of light =
m = Mass of proton=
q = Charge of electron =
Acceleration is given by
Dividing by g
The acceleration is or
The distance is 23.4843749996 m
The gravitational field is very small compared to the electric field so the effects of gravity can be ignored.
Answer:
Explanation:
This problem can be solved with the conservation of the momentum.
If the ball is fired upward, the momentum before and after the ball is fired must conserve. Hence, the speed of the ball is the same that the speed of the car just in the moment in wich the ball is fired.
Hence, the result depends of the acceleration of the car. If the change in the speed is higher than the speed of the ball, it is probably that the ball will be behind the car or it will come back to the car.
If the ball is fired forward, and if the change in the speed of the car is not enogh, the ball will be in front of the car.
HOPE THIS HELPS!!