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rewona [7]
3 years ago
12

THE PROBLEM!

Physics
1 answer:
Elodia [21]3 years ago
3 0

Answer: 15.29

Explanation: there you go have a nice day (*^p^*)

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Answer:

28.8 meters

Explanation:

We must first determine at which velocity the ball hits the water. To do so we will:

1) Assume no air resistance.

2) Use the Law of conservation of mechanical energy: E=K+P

Where

E is the mechanical energy (which is constant)

K is the kinetic energy.

P is the potential energy.

With this we have \frac{m}{2} *v^{2}  = m*g*h

Where:

m is the balls's mass <- we will see that it cancels out and as such we don't need to know it.

v is the speed when it hits the water.

g is the gravitational constant (we will assume g=9.8\frac{m}{s^{2} }.

h is the height from which the ball fell.

Because when we initially drop the ball, all its energy is potential (and P = - m*g*h) and when it hits the water, all its energy is kinetic (K=\frac{m}{2} *v^{2}. And all that potential was converted to kinetic energy.

Now, from \frac{m}{2} *v^{2}  = m*g*h we can deduce that v=\sqrt{2*g*h}

Therefore v=9.6\frac{m}{s}

Now, to answer how deep is the lake we just need to multiply that speed by the time it took the ball to reach the bottom.

So D=9.6\frac{m}{s}*3s=28.8m

Which is our answer.

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