Answer:
Explanation: you can choose B or C but i would choose C
A short circuit is said to have occurred when two nodes of a circuit at different voltages are abnormally connected
There is said to be a short circuit when; <u>One part of a parallel circuit has a very low resistance and almost all the current will flow through this part and very little current will flow through the other part</u>
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The correct option is option B.
Reason:
A circuit has to be closed or the the current path has to be closed for
current to flow. A short circuit occurs when current in a circuit flows
through an abnormal path, such as a bridge in a connection to a load that
creates a parallel path for current flow.
Almost all the current flows through the parallel path due to the low
resistance in the connection (almost zero) and the proximity to the power
source, thereby preventing current from reaching its intended destination
Therefore, the correct option is option B.;
Learn more here:
brainly.com/question/23779827
brainly.com/question/19912277
You sketch a water molecule and show a partial positive charge on the two Hydrogen atoms and a partial negative charge on the oxygen atom.
Answer:
v = 15 m / s
Explanation:
In this exercise we are given the position function
x = 5 t²
and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval
let's look for the displacements
t = 0 x₀ = 0 m
t = 3 
= 5 3 2
x_{f} = 45 m
we substitute
v = 15 m / s
Answer:
4.8L ( i.e 4.8 x 10^-3 m3)
Explanation:
Step 1:
Data obtained from the question.
Initial volume (V1) = 4.2L
Initial temperature (T1) = 0°C
Final temperature (T2) = 37°C
Final volume (V2) =?
Step 2:
Conversion of celsius temperature to Kelvin temperature. This is illustrated below
K = °C + 273
T1 = 0°C = 0°C + 273 = 273K
T2 = 37°C = 37°C + 273 = 310K
Step 3:
Determination of the final volume.
Since the pressure is constant,
Charles' Law equation will be applied as shown below:
V1 /T1 = V2/T2
4.2/273 = V2 /310
Cross multiply to express in linear form
273 x V2 = 4.2 x 310
Divide both side by 273
V2 = (4.2 x 310)/273
V2 = 4.8L ( i.e 4.8 x 10^-3 m3)
Therefore, the volume of the air in the lungs at that point is 4.8L ( i.e 4.8 x 10^-3 m3)
