Molar mass of H₂ = 1.008 × 2 g/mol = 2.016 g/mol <span>
Molar mass of I₂ =
126.9 × 2 g/mol = 253.8 g/mol </span><span>
Molar mass of HI = (1.008 + 126.9) g/mol = 127.9 g/mol
H₂(g) + I₂(g) → 2HI </span><span>
Mole ratio H₂ : I₂ : HI = 1 : 1 : 2 </span><span>
Then the initial number of moles of H₂ = (3.35 g) / (2.016 g/mol) = 1.662 mol </span><span>
Initial number of moles of I₂ = (50.75 g) / (253.8 g/mol) = 0.2000 mol <
1.662 mol </span><span>
Hence, I₂ is the
limiting reactant (limiting reagent). </span><span>
Number of moles of I₂ reacted = 0.2000 mol </span><span>
Number of moles of HI reacted = (0.2000 mol) × 2 = 0.4000 mol
<span>Mass of HI reacted = (127.9 g/mol) × (0.4000 mol) = 51.16 g</span></span>
H's result was one dead flower ... not surprising ... stuck in a dark room = no photosynthesis = no growth = death.
H loses is "control" part of his "experiment".
Q gives no idea the colour of H's flowers in expt.
H "shows" that a watered plant in sunlight with a bit of fetilizer tends to grow. He could have had a look outside at a garden to see that.
improvement by not killing the "control" plant. put it side by side with the test plant, so both get the photo stuff. Then measured fertilizer in test plant, and same water minus fert in control.
As for the colour I've no idea.
Answer:
As the particles move further away from their normal position (up towards the wave crest or down towards the trough), they slow down.
Explanation:
This means that some of their kinetic energy has been converted into potential energy – the energy of particles in a wave oscillates between kinetic and potential energy. Hope that this helps you and have a great day :)
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