According to Newton’s second law of motion:
F=ma
=80*0.5
=40N
The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s
Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:
<h3>Speed = distance / time </h3>
With the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:
Distance = 7 m
Speed of light = 3×10⁸ m/s
<h3>Time =?</h3>
Time = Distance / speed
Time = 7 / 3×10⁸
<h3>Time = 2.33×10¯⁸ s</h3>
Therefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s
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Answer:
Explanation:
given,
charge = -5.0 μC
Electric force, F = 11 i^ N
force would a proton experience = ?
we know
we know charge of proton is equal to 1.6 x 10⁻¹⁹ C
using formula
Force experienced by the photon in the same field is equal to
The area-
The area under the line in a velocity-time graph represents the distance travelled. To find the distance travelled in the graph above, we need to find the area of the light-blue triangle and the dark-blue rectangle.
<span><span>Area of light-blue triangle -
<span>The width of the triangle is 4 seconds and the height is 8 meters per second. To find the area, you use the equation: <span>area of triangle = 1⁄2 × base × height </span><span>so the area of the light-blue triangle is 1⁄2 × 8 × 4 = 16m. </span></span></span><span> Area of dark-blue rectangle
The width of the rectangle is 6 seconds and the height is 8 meters per second. So the area is 8 × 6 = 48m.</span><span> Area under the whole graph
<span>The area of the light-blue triangle plus the area of the dark-blue rectangle is:16 + 48 = 64m.<span>This is the total area under the distance-time graph. This area represents the distance covered.</span></span></span></span>
Answer:
True
True statement:
Because pigment molecules absorb solar energy and thylakoids are pigment molecules
