Answer:s=0.68 m
Explanation:
Given
Inclination
Speed of block(u)=1.6 m/s
Coefficient of kinetic Friction
deceleration provided by friction=g\sin \theta -\mu _kg\cos \theta [/tex]
Using
Final velocity v=0
s=0.68 m
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Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back
From the question we are told
If the average velocity during the athlete's walk back to the starting line in Guided Example 2.5 is – 1.50 m/s,
Generally the equation Time spent is mathematically given as
T=\frac{d}{v}
Therefore
Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back
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