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liberstina [14]

3 years ago

11

A 19kg block is being pulled with a constant horizontal force of 95 Newton’s while also experiencing a constant friction force o

f 19 Newton’s. Determine the horizontal acceleration. Show all your work and include units in your answer

1 answer:

yuradex [85]3 years ago

5 0

Answer:

A

⋅(19kg)=19Akg

95=19Akg

19=19Ak

Explanation:

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Solution :

c). $\vec{F}_A =$ force applied by Abe

$\vec{F}_B =$ force applied by Barry

$\vec{F}_E =$ force applied by Eric

$\vec{F}_R =$ Resultant force

$\vec{F}_A$ in the vector form can be written as :

$\vec{F}_A = 0 \hat{i} + 60 \hat{j}$

$\vec{F}_B$ in the vector form can be written as :

$\vec{F}_B = 60 \hat{i} + 0 \hat{j}$

The resultant,

$\vec{F}_R= \vec{F}_A+\vec{F}_B$

$=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$

$=60 \hat i + 60 \hat j$

$|\vec{F}_R| = \sqrt{60^2+60^2}$

= 84.853 N

d). As the three forces are in equilibrium, therefore,

$|\vec F_E| = |\vec F_R|$

$|\vec F_E| =84.853 \ N$

e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.

The direction of the resultant force is :

$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$

$= \tan ^{-1}\left(\frac{60}{60}\right)$

= 45° north east

The direction of the force E is 45° west or 45° south west.

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Between which two points of a concave mirror should an object be placed to obtain a magnificati of -3

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Answer:

When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.

When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.

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A wooden walkway and a sandy beach are at the same temperature. the sand feels much hotter because it has a greater _____.

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As it has a greater specific capacity than wood, it takes more heat energy to increase it's temperature by 1 degree Celsius than that of wood. Hence, though both are at the same temperature, sand contains way more heat than wood.

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3 years ago

A 1 m long wire of diameter 1mm is submerged in an oil bath of temperature 25-degC. The wire has an electrical resistance per un

Zarrin [17]

Answer:

steady state temperature =88.7deg C

t=time within 1 deg C of it steady state is 8.31s

Explanation:

A 1 m long wire of diameter 1mm is submerged in an oil bath of temperature 25-degC. The wire has an electrical resistance per unit length of 0.01 Ω/m. If a current of 100 A flows through the wire and the convection coefficient is 500W/m2K, what is the steady state temperature of the wire? From the time the current is applied, how long does it take for the wire to reach a temperature within 1-degC of the steady state value? The density of the wire is 8,000kg/m3, its heat capacity is 500 J/kgK and its thermal condu

The diameter of the wire is known to be=1mm

properties=

The density of the wire is 8,000 kg/m3,

heat capacity is 500 J/kgK

themal conductivity is 20W/m.K

electrical resistance per unit length of 0.01 Ω/m

from lump capavity method

$B_{i} =\frac{hr/2}{k}$

500*(2.5*10^-4)/20

0.006<0.1

we know also, to find steady state temperature

$\pi$ Dh(T-Tinf)= $I^{2} R_{e}$

make T the subject of the equation , we have

T=25+ $\frac{100^2*0.01}{\pi*0.001*500 }$

T=88.7 degC

rate of chnage in temperature

dT/dt= $\frac{I^2*Re}{rho*c*\pi*D^2/4 } -\frac{4h}{rho*c*D} (T-Tinf)$

at t=o and integrating both sides $\frac{T-Tinf-(I^2*Re/\pi*Dh) }{Ti-Tinf-(I^2*Re/\pi*Dh } =exp\frac{-4ht}{rho*c*D}$

we have

$\frac{87.7-25-63.7}{25-25-63.7} =exp\frac{4*500t}{8000*500*0.001}$

t=8.31s

steady state temperature =88.7deg C

t=time within 1 degC of it steady stae is 8.31s

7 0

3 years ago