Answer : The correct option is A.
Explanation :
The given chemical reaction is,
In the reaction, Reactants are present on the left side of the arrow and products are present on the right side of the arrow.
Reactants are those which takes part in and undergoes change during the reaction.
Products are those which are formed during the reaction.
In the given reaction, zinc react with hydrochloric acid to form zinc chloride and hydrogen gas.
Therefore, the reactants are zinc and hydrochloric acid.
Answer:
B will give up two electrons to form bonds.
Explanation:
B has 12 electrons, it means that the electronic configuration of B is; 1s2 2s2 2p6 3s2. The implication of this is that B must be an element of group 2 since it has an outermost electron configuration of ns2.
The elements of group 2 form ionic bonds by loss of two electrons. This implies that B will form bonds by loss of two electrons.
Answer:
D) both the solid and the liquid phase
Explanation:
Metallic substances will conduct electricity in both the solid and liquid phase. Metals are generally conductors of heat and electricity.
- In metals there are free mobile electrons the enables the flow electricity.
- The free mobile electrons is utilized by the metals to conduct electricity.
- Metals generally have metallic bonds that holds their particles together.
- The metallic bonds enables metals to have a sea of delocalized electrons.
- Metals have a large atomic radius and larger electron pool.
Answer:
The second friend is mostly correct.
Explanation:
When pressure decreases, gas solubility decreases. The bubbles are gas molecules that were dissolved in the water at atmospheric pressure. The bubbles started coming out as a result of the decrease pressure. The second bubbles would be water vapor because as the pressure continue to decrease, the amount of vapor pressure ( vapor leaving the surface of the liquid ) equals the external pressure and water begin to boil. So the second bubbles must be water vapor.
Answer:
Find the list and explanation below.
Explanation:
Hydrochloric acid shortened as HCl is a harmful chemical when not handled properly. Four ways to avoid injury with hydrochloric acid include;
1. Dilution: It is advised to dilute the concentrated hydrochloric acid with a reasonable amount of water so that its corrosive effect can be significantly reduced.
2. Wear a laboratory coat: When working with hydrochloric acid in the laboratory it is always advised to wear a laboratory suit so as to ensure a minimal amount of harm in case of an accident or spillage with the acid.
3. Wear a face shield: It is also important that a face shield is worn while working with the acid to prevent contact with the eyes.
4. Wear a protective rubber glove: The rubber gloves would ensure that there is minimal contact of the acid with the hands.
Three steps to be taken in case of an accidental exposure include;
1. Medical Attention: In serious cases, such as in a case of ingesting the acid, urgent medical help should be sought for immediately.
2. Water: If there is contact with the skin or eye, a lot of water should be used on the affected area, and then medical help obtained.
3. Inhalation of fresh air: In a case whereby the hydrochloric acid was inhaled for a long time, the affected person should try to get some fresh air and if other effects are noticed, urgent medical attention should be gotten.
