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vesna_86 [32]
3 years ago
14

Axial flowers are a dominant trait in pea plants, and terminal flowers are a recessive trait. Which genotype represents a plant

that has homozygous dominant genes for axial flowers?
aa
Aa
AA
AAaa
Chemistry
2 answers:
kolbaska11 [484]3 years ago
3 0
As the plant is Homozygous dominant, it must contains, two capital "A"s mentioned above.

In short, Your Answer would be Option C

Hope this helps!
Lapatulllka [165]3 years ago
3 0

Answer:

AA

Explanation:

In genetics a dominant trait is represented with a capital letter. And the recessive trait always with lowercase. When we are talking about a specimen being homozygous, it means that it has both equal alleles (AA or aa). And if you talk about it being heterozygous, the two alleles are different (Aa).

In this case the dominant allele would be "A".

And since it is homozygous, it corresponds to both alleles being equal (AA).

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PbSO4 has a Ksp = 1.3 * 10-8 (mol/L)2.
Oduvanchick [21]

i. The dissolution of PbSO₄ in water entails its ionizing into its constituent ions:

\mathrm{PbSO_{4}}(aq) \rightleftharpoons \mathrm{Pb^{2+}}(aq)+\mathrm{SO_4^{2-}}(aq).

---

ii. Given the dissolution of some substance

xA{(s)} \rightleftharpoons yB{(aq)} + zC{(aq)},

the Ksp, or the solubility product constant, of the preceding equation takes the general form

K_{sp} = [B]^y [C]^z.

The concentrations of pure solids (like substance A) and liquids are excluded from the equilibrium expression.

So, given our dissociation equation in question i., our Ksp expression would be written as:

K_{sp} = \mathrm{[Pb^{2+}] [SO_4^{2-}]}.

---

iii. Presumably, what we're being asked for here is the <em>molar </em>solubility of PbSO4 (at the standard 25 °C, as Ksp is temperature dependent). We have all the information needed to calculate the molar solubility. Since the Ksp tells us the ratio of equilibrium concentrations of PbSO4 in solution, we can consider either [Pb2+] or [SO4^2-] as equivalent to our molar solubility (since the concentration of either ion is the extent to which solid PbSO4 will dissociate or dissolve in water).

We know that Ksp = [Pb2+][SO4^2-], and we are given the value of the Ksp of for PbSO4 as 1.3 × 10⁻⁸. Since the molar ratio between the two ions are the same, we can use an equivalent variable to represent both:

1.3 \times 10^{-8} = s \times s = s^2 \\s = \sqrt{1.3 \times 10^{-8}} = 1.14 \times 10^{-4} \text{ mol/L}.

So, the molar solubility of PbSO4 is 1.1 × 10⁻⁴ mol/L. The answer is given to two significant figures since the Ksp is given to two significant figures.

8 0
3 years ago
How much heat is released when 6.00 g of methane is combusted using the reaction below? CH4 + 2O2 ? CO2 + 2H2O ?Hrxn = -890. KJ
goblinko [34]

Answer : The amount of heat released is, -121.04 KJ

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Enthalpy of reaction, \Delta H_{rxn} = -890 KJ

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First we have to calculate the moles of methane.

\text{Moles of methane}=\frac{\text{Mass of methane}}{\text{Molar mass of methane}}=\frac{6g}{44g/mole}=0.136moles

The given balanced reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

1 mole of methane releases heat = -890 KJ

0.136 moles of methane releases heat = \frac{0.136moles}{1mole}\times -890KJ=-121.04KJ

Therefore, the amount of heat released is, -121.04 KJ

8 0
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