Answer:
Double bonds. It says I have to write more words lol but yeah it's double bonds
Calorie (cal) or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.
One small calorie is approximately 4.2 joules.
A calorie is a unit of energy.
For example:
Q = 150000 J; released energy.
Convert Jules in calories:
Q = 150000 J ÷ 4.186 J/calorie.
Q = 35833.73 calorie.
The large calorie or nutritional calorie (symbols: Cal, kcal) is the heat energy needed to raise the temperature of one kilogramof water by one degree Celsius.
A nutritional calorie, or kilocalorie, is equal to 1000 calories.
One large calorie is 4.184 kilojoules: 1 Cal = 4.184 kJ.
For example:
E = 2500 Cal; energy burnt.
E = 2500 Cal · 4.184 kJ/Cal.
E = 10460 kJ.
Answer:
<h2>HERE'S YOUR ANSWER </h2>
We are given that the ring is made up of 20 carrat gold. 20 carrat gold means 20 parts of gold and 4 parts of other metal (usually copper or silver). Thus, the percentage of gold in 20 carrat gold will be
= (20 / 24) X 100
= 83.333 %
We can now calculate the mass of gold in the ring. We are given that the ring weighs 300 mg. So, the mass of gold in ring will be
= (83.333 / 100) X 300
= 250 mg
Thus, the mass of gold in 300 mg of the ring is 250 mg.
Now the molar mass of gold is 197 g. This means that there are 6.023 X 1023 atoms of gold in 197g of gold. Thus
197g of gold = 6.023 X 1023 atoms of gold
1g of gold = (6.023 X 1023 ) / 197 atoms of gold
250 mg or 0.25g of gold = (6.023 X 1023 X 0.25) / 197 atoms of gold
= 7.643 X 1020 atoms of gold
<h2>HOPE IT HELPS MAN ☺️</h2>
Answer:
There are 9 protons and 9 neutrons. there are 10 electrons
Explanation:
Oxidation-reactions are equations where some species release electrons and other species gain electron.
So two reactions happen simultaneously the oxidation of one species and the reduction off the other species.
In the oxidations, the species release electrons and, consequently, increase their oxidation number.
In the reductions, the species gain electrons and, consequently, decrease their oxidation number.
This last reaction, reduction, is what the above equation represents: Sn 4+ is gaining 2 electrons and so its oxidation number decrease from 4+ to 2+.
In, conclusion that is a reduction equation (option d)
