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3 years ago

BRAINLIESTTT ASAP !! PLEAASE HELP ME :) Describe the image below in detail.

Chemistry

1 answer:

Maru [420]3 years ago

5 0

The periodic table of 118 elements of chemistry..

The table devided into row and columns
The seven horizontal rows of elements called periods
And eighteen verticals line called group...

hope it helps u

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Select the correct equalities for the units shown.

elena-14-01-66 [18.8K]

Answer

1. 1cm=10mm, 1kg=1000g and 12in=1 ft

2. 50mm=5cm

48 in =4ft

36ft=12 yd

2.5m=250cm

1000mL= 1 L

Explanation

if 1cm=10mm then 5cm=?

5×10=50mm

if 12 in =1ft then 48in=?

48/12 =4 ft

if 1m=100cm, then 2.5m=?

2.5×100= 250cm

and when know from capacity that 1000mL is equivalent to 1 liter.

7 0

3 years ago

Read 2 more answers

Identify the highlighted secondary lymphatic tissue located on the lateral wall of the oropharynx just inferior to the soft pala

Katena32 [7]

Answer:

The correct answer is - palatine tonsils .

Explanation:

Palatine tonsils or more normally tonsils are the pair of soft tissue masses of highlighted secondary lymphatic tissue present on the lateral wall of the oropharynx in the tonsilar fossa just below to the soft plate. It is the lymphatic tissue that is located to inferior to the soft plate.

Thus, the correct answer is - palatine tonsils.

6 0

3 years ago

In a body of water, the surface tension caused by the attraction between water molecules is strong. Which of the following is a

Marina86 [1]

<span>Answer: Objects with a higher density than water can be observed floating on water

Water spider is one of the animals that can walk above the water. The legs of the spyder float because the force that it gives to the water surface is not higher than the surface tension, thus the water didn't break. Even though the spider density is higher than water, it could look like floating above the water.</span>

3 0

3 years ago

Read 2 more answers

Consider the reaction N2(g) + 2O2(g)2NO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr

zysi [14]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$N_2+2O_2\rightarrow 2NO_2$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(NO_2(g))})]-[(1\times \Delta S^o_{(N_2(g))})+(2\times \Delta S^o_{(O_2(g))})]$

We are given:

$\Delta S^o_{(NO_2(g))}=240.06J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(N_2)}=191.61J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (240.06))]-[(1\times (191.61))+(2\times (205.14))]\\\\\Delta S^o_{rxn}=-121.77J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-121.77) J/K = 121.77 J/K

We are given:

Moles of nitrogen gas reacted = 1.90 moles

By Stoichiometry of the reaction:

When 1 mole of nitrogen gas is reacted, the entropy change of the surrounding will be 121.77 J/K

So, when 1.90 moles of nitrogen gas is reacted, the entropy change of the surrounding will be = $\frac{121.77}{1}\times 1.90=231.36 J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

7 0

3 years ago

If a gas is initially at a pressure of nine ATM and a volume at 21 L at a temperature of 253K and the pressure is raise to 15 AT

Tom [10]

Answer:

15.0L

Explanation:

p/v = constan

(9*21)/253 =(15v)/ 302

v = (9*21*302)/(15*253)

v=15.0

3 0

3 years ago