Answer:
i think the answer is Continental polar air masses
Explanation:
Answer:
V = 3.1 L
Explanation:
Given data:
Molarity of solution = 0.37 M
Mass of LiF = 29.53 g
Volume of solution = ?
Solution:
Number of moles of LiF:
Number of moles = mass/molar mass
Number of moles = 29.53 g/ 25.94g/mol
Number of moles = 1.14 mol
Volume:
Molarity = number of moles of solute / Volume in L
0.37 M = 1.14 mol / V
V = 1.14 mol / 0.37 M
V = 3.1 L (M = mol/L)
I believe it would be Au^4Cl8
The chemical reaction is written as:
2Zn + O2 = 2ZnO
We are given the amount of the product to be produced from the reaction. We use this value and the relation of the substances in the reaction to calculate what is asked. We do as follows:
2.10 g ZnO ( 1 mol / 81.408 g ) ( 1 mol O2 / 2 mol ZnO ) ( 32 g / 1 mol ) = 0.414 g O2 is needed
