In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=
1 answer:
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On ground weight of plane will be measured as its actual weight which will be given as
now when plane is in air its weight is measured as combined effect of earth gravitational force and buoyancy force both
so weight in air will be given as
here since net effect due to air is opposite to the direction of weight so in air the plane weight will be measure less than its weight on ground.
so answer will be
A)more than a plane in the air
Answer:
The block will be move in to right side.
Explanation:
Given that,
Mass of block = 2 kg
First force = 3 N
Second force = 4 N
We need to calculate the acceleration
For first force,
Using newton's second law
Put the value into the formula
We need to calculate the acceleration
For second force,
So, we can say that the block will be move to right side because the acceleration is maximum in to right side.
Hence, The block will be move in to right side.
Answer:
Resultant displacement = 38.58 miles at an angle of 23.57° north of west.
Explanation:
Let north represent positive y direction and east represent positive x direction. Unit vector along x direction is represented by i and vector along unit vector along y direction is represented by j
Initial displacement = 17 miles north = 17 j miles
Final displacement = 24 miles at an angle of 40° west of north = 24 miles at an angle of 130° to positive x -axis
= (24 cos 130 i + 24 sin 130 j )
= (-15.43 i + 18.36 j ) miles
Total displacement = 17 j + (-15.43 i + 18.36 j) = -15.43 i + 35.36 j
Magnitude of displacement
Angle to positive x -axis = tan⁻¹(35.36/-15.43) = 113.57°
Resultant displacement = 38.58 miles at an angle of 23.57° west of north.