The velocity of the submarine immediately after firing the missile is 0.0104 m/s
Explanation:
Mass of the submarine M=50 tonne=
Mass of the missile m=40 kg
velocity of the missile v= 13m/s
we have to calculate the velocity of the submarine after firing
This is the recoil velocity and its expression is derived from the law of conservation of momentum
recoil velocity of the submarine

Answer: The motions shifts.
There are 8 electrons in the third energy level of Calcium atom.
Answer:
W = 735.75[J]
Explanation:
Work is defined as the product of force by distance. Therefore we can use the following equation.

where:
W = work [J] (units of Joules)
F = force [N] (units of Newtons)
d = distance = 3 [m]
But first, we must determine the force that is equal to the product of mass by gravity (weight of the body).
![F=m*g\\F=25*9.81\\F=245.25[N]](https://tex.z-dn.net/?f=F%3Dm%2Ag%5C%5CF%3D25%2A9.81%5C%5CF%3D245.25%5BN%5D)
![W=F*d\\W=245.25*3\\W=735.75[J]](https://tex.z-dn.net/?f=W%3DF%2Ad%5C%5CW%3D245.25%2A3%5C%5CW%3D735.75%5BJ%5D)