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3 years ago

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PLEASE HELP URGETNT

1 answer:

Angelina_Jolie [31]3 years ago

6 0

Answer:

I think (d) is right answer

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You see an image of yourself in a mirror because light waves are A) diffracted. B) reflected back at you. C) refracted through a

kondaur [170]

Answer:

(b) reflected back at you

Explanation:

6 0

4 years ago

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A stone is dropped at t = 0. A second stone, with twice the mass of the first, is dropped from the same point at t = 181 ms. How

lara [203]

Answer:

the center of mass is 316,670m bellow the release point.

Explanation:

First, we must find the distance at which the objects are in time t = 360s

We will use the formula for vertical distance in free fall

$h=v_{0}t+\frac{1}{2} gt^2$

$v_{0}$ is the initial velocity, is 0 for both stones since they were just dropped.

g is acceleration of gravity and t is time ( $g=9.81m/s^2$ )

At $t=360s$ the first stone has been falling for the entire 360 seconds, its position h1 is:

$h_{1}=\frac{1}{2} (9.82m/s^2)(360s^2)=635,688m$

And at 360 seconds the second stone has been fallin for $t= 360s -181 s = 179s$ , so its position h2 is:

$h_{2}=\frac{1}{2} (9.81m/s^2)(179)^2=157,161.1m$

And finally using the equation for the center of mass:

$CM=\frac{m_{1}h_{1}+m_{2}h_{2}}{m_{1}+m_{2}}$

We know that the mass of the second stone is twice the mass of the first stone so:

$m_{1}=m\\m_{2}=2m$

replacing these values in the equation for the center of mass

$CM=\frac{mh_{1}+2mh_{2}}{m+2m}$

$CM=\frac{m(h_{1}+2h_{2})}{3m}=\frac{h_{1}+2h_{2}}{3}$

Finally, replacing the values we found fot h1 and h2:

$CM=\frac{635,688m+2(157,161.1m)}{3}=316,670m$

the center of mass is 316,670m bellow the release point.

8 0

4 years ago

How does the earth move within the solar system?

Morgarella [4.7K]

The earth rotates (spins) at the same time as it orbits in a circular motion around the sun. fun fact : it takes 365 days to complete 1 orbit for 3 years and then 366 days for a leap year! you don't have to put that last part but maybe for some extra points you can!

7 0

3 years ago

The Milky Way galaxy (pictured above) is an example of a(n) __________________ galaxy. At the center of the galaxy is a galactic

OlgaM077 [116]

I think the answer is A.

8 0

3 years ago

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A golf club exerts an average horizontal force of 1005 N in the –x direction on a 453 grams golf ball that is initially at rest

adelina 88 [10]

Answer:

The impulse is 1.89 Ns and final velocity of the golf 4.17 $\frac{m}{s}$

Explanation:

Given:

Average force $F = 1005$ N

Contact time $t = 1.89 \times 10^{-3}$ sec

Mass of golf ball $m = 453 = 0.453$ kg

(a)

Impulse is given by,

$J = Ft$

$J = 1005 \times 1.89 \times 10^{-3}$

$J = 1.89$ Ns

(b)

For finding the final velocity,

$J = \Delta P$

$J = mv$

$1.89 = 0.453 v$

$v = 4.17 \frac{m}{s}$

Therefore, the impulse is 1.89 Ns and final velocity of the golf 4.17 $\frac{m}{s}$

7 0

3 years ago