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garri49 [273]
2 years ago
5

You are going 30 m/s in a car of mass 1000 kg when you reach a red light and stop your car.

Physics
1 answer:
Radda [10]2 years ago
5 0

Answer:

Explanation:

The kinetic energy will convert to heat energy (provided the car has friction brakes and not regenerative brakes as might be found on an electric or hybrid) Also<u> assuming level road</u>.

E = ½mv² = ½(1000)30² = 450,000 J

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A spring hangs at rest from a support. If you suspend a 0.46 kg mass from the spring it elongates 0.79m.
Fudgin [204]

a. The restoring force in the spring has magnitude

F[spring] = k (0.79 m)

which counters the weight of the mass,

F[weight] = (0.46 kg) g = 4.508 N

so that by Newton's second law,

F[spring] - F[weight] = 0   ⇒   k = (4.508 N) / (0.79 m) ≈ 5.7 N/m

b. Using the same equation as before, we now have

F[weight] = (0.75 kg) g = 7.35 N

so that

(5.7 N/m) x - 7.35 N = 0   ⇒   x = (7.35 N) / (5.7 N/m) ≈ 1.3 m

4 0
2 years ago
A girl scout is pulling her 30 kg wagon of cookies with a force of 60 N to right. Friction pulls back with a force of 15 N left.
andreyandreev [35.5K]

Answer:

net force = 45 newton towards right

8 0
2 years ago
How can the rate of a reaction be increased?
xeze [42]

I  think it is D- diluting a solution sorry if i am wrong

7 0
3 years ago
In a wire with a 1.05 mm2 cross-sectional area, 7.93×1020 electrons flow past any point during 3.97 s. What is the current ????
34kurt

Answer:

The current in the wire is 31.96 A.

Explanation:

The current in the wire can be calculated as follows:

I = \frac{q}{t}

<u>Where</u>:

q: is the electric charge transferred through the surface

t: is the time      

The charge, q, is:

q = n*e

<u>Where</u>:

n: is the number of electrons = 7.93x10²⁰

e: is the electron's charge = 1.6x10⁻¹⁹ C

q = n*e = 7.93 \cdot 10^{20}*1.6 \cdot 10^{-19} C = 126.88 C

Hence, the current in the wire is:

I = \frac{126.88 C}{3.97 s} = 31.96 A

Therefore, the current in the wire is 31.96 A.

I hope it helps you!

3 0
3 years ago
30
BARSIC [14]

Answer:

The correct answer is Tor buni aga daka pagli Tor buda mu tor buni kaitam chai ami

5 0
3 years ago
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