a. The restoring force in the spring has magnitude
F[spring] = k (0.79 m)
which counters the weight of the mass,
F[weight] = (0.46 kg) g = 4.508 N
so that by Newton's second law,
F[spring] - F[weight] = 0 ⇒ k = (4.508 N) / (0.79 m) ≈ 5.7 N/m
b. Using the same equation as before, we now have
F[weight] = (0.75 kg) g = 7.35 N
so that
(5.7 N/m) x - 7.35 N = 0 ⇒ x = (7.35 N) / (5.7 N/m) ≈ 1.3 m
I think it is D- diluting a solution sorry if i am wrong
Answer:
The current in the wire is 31.96 A.
Explanation:
The current in the wire can be calculated as follows:

<u>Where</u>:
q: is the electric charge transferred through the surface
t: is the time
The charge, q, is:

<u>Where</u>:
n: is the number of electrons = 7.93x10²⁰
e: is the electron's charge = 1.6x10⁻¹⁹ C

Hence, the current in the wire is:

Therefore, the current in the wire is 31.96 A.
I hope it helps you!
Answer:
The correct answer is Tor buni aga daka pagli Tor buda mu tor buni kaitam chai ami