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2 years ago

How many o atoms are in 259 g of c12h21o9? molar mass of c12h21o9 = 309.29 g/mol

Chemistry

2 answers:

Triss [41]2 years ago

8 0

The number of atoms in 259 g of C₁₂H₂₁O₉ is 45 x 10²³ oxygen.

<h3>What is molar mass?</h3>

The molar mass of many compounds can be calculated by dividing the mass of the compound by the number of moles of the compound.

Given the molar mass is 309.29 g/mol

Given weight= 259g

number of moles = mass / molar mass

259g / 309.29g/mol =0.837mol

1 mol contains 6.022 x 10²³ molecules

0.837 mol contain 6.022 x 1023 x 0.837 = 5.0 x 10²³ molecules

1 molecule of C₁₂H₂₁O₉ contains 9 oxygen atoms

5.0 x 10²³ molecules of C₁₂H₂₁O₉ contain 9x 5 x 10²³ oxygen atoms.

=45 x 10²³ oxygen atoms

Thus, the number of atoms in 259 g of C₁₂H₂₁O₉ is 45 x 10²³ oxygen atoms

To learn more about molar mass, refer to the link:

brainly.com/question/22997914

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blsea [12.9K]2 years ago

7 0

Answer:

Explanation: your the best

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adoni [48]

Answer:

185 gms o NaBr

Explanation:

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2 years ago

KNO3(s) --> K+(aq) + NO3-(aq)This reaction was carried out in a Styrofoam insulated calorimeter and the following data were r

nataly862011 [7]

Answer:

Equation correctly showing the heat of solution

$KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)$

Explanation:

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Change in temperature = $\Delta T=T_f-T_i$

ΔT = 21.6ºC - 30.0ºC = -8.4ºC

Heat lost by the solution = Q

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Q = -3,511.2 J ≈ -3.51 kJ

Heat absorbed by potassium nitrate when solution in formed; Q'

Q' = -Q = 3.51 kJ

Moles of potassium nitrate , n= $\frac{10.1 g}{101 g/mol}=0.1 mol$

$KNO_3(s)\rightarrow K^+(aq) + NO_{3}^-(aq)$

The heat of solution =

$\frac{Q'}{n}=\frac{3.5112 kJ}{0.1 mol}=35.1 kJ/mol$

So, the equation correctly showing the heat of solution

$KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)$

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