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Alexxandr [17]
2 years ago
13

What is a primary concern for residential sprinkler systems installed according to nfpa?

Engineering
1 answer:
kakasveta [241]2 years ago
6 0

The residence sprinkler is intended for use in residential settings when the major concern is the life security of those inside the original room.

<h3>What is a residential sprinkler?</h3>

An array of sprinkler heads coupled with water mains within the house make up a domestic sprinkler system. A dependable source of water, such as a tank or a communal water supply, supplies the network.

The primary concern for residential sprinkler systems installed according to NFPA will be

The residential sprinkler is intended for use in domestic settings when the real problem is the life protection of those inside the original room.

More about the residential sprinkler link is given below.

brainly.com/question/3445302

#SPJ4

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A sinusoidal voltage source produces the waveform, v t = 1 + cos 2πft. Design a system with v t as its input such that an LED wi
DerKrebs [107]

Answer:

See explaination

Explanation:

LM358 is the useful IC which works as buffer. It enables circuit to remove overloading effect on each other. Image is in attachment.

We can define a light-emitting diode (LED) as a semiconductor light source that emits light when current flows through it. Electrons in the semiconductor recombine with electron holes, releasing energy in the form of photons

See attached file for detailed solution of the given problem.

3 0
3 years ago
An alloy is evaluated for potential creep deformation in a short-term laboratory experiment. The creep rate is found to be 1% pe
LenaWriter [7]

Answer:

a) Q = 251.758 kJ/mol

b) creep rate is    = 1.751 \times 10^{-5} \% per hr

Explanation:

we know Arrhenius expression is given as

\dot \epsilon =Ce^{\frac{-Q}{RT}

where

Q is activation energy

C is pre- exponential constant

At 700 degree C creep rate is\dot \epsilon = 5.5\times 10^{-2}% per hr

At 800 degree C  creep rate is\dot \epsilon = 1% per hr

activation energy for creep is \frac{\epsilon_{800}}{\epsilon_{700}} = = \frac{C\times e^{\frac{-Q}{R(800+273)}}}{C\times e^{\frac{-Q}{R(700+273)}}}

\frac{1\%}{5.5 \times 10^{-2}\%} = e^{[\frac{-Q}{R(800+273)}] -[\frac{-Q}{R(800+273)}]}

\frac{0.01}{5.5\times 10^{-4}} = ln [e^{\frac{Q}{8.314}[\frac{1}{1073} - \frac{1}{973}]}]

solving for Q we get

Q = 251.758 kJ/mol

b) creep rate at 500 degree C

we know

C = \epsilon e^{\frac{Q}{RT}}

    =- 1\% e{\frac{251758}{8.314(500+273}} = 1.804 \times 10^{12} \% per hr

\epsilon_{500} = C e^{\frac{Q}{RT}}

                         = 1.804 \times 10^{12}  e{\frac{251758}{8.314(500+273}}

                         = 1.751 \times 10^{-5} \% per hr

4 0
3 years ago
This is an essential safety procedure that protects workers from injury while working on or near electrical circuits and equipme
Mice21 [21]

Answer:

Option B

Lockout/ Tagout

Explanation:

lockout and tagout is a safety procedure used in most industries and work places. This ensures that during any maintenance work, that dangerous machines are properly shut off and not able to be started up again prior to the completion of maintenance or repair work.

The procedure includes:

1. Turns off and disconnects the machinery or equipment from its energy source(s) before performing service or maintenance.

2. The authorized employee(s) either lock or tag the energy-isolating device(s) to prevent the release of hazardous energy.

8 0
4 years ago
The criminal and traffic code requires that a driver must have a valid driver's license in his/her
ankoles [38]

Answer:

true

Explanation:

the answer is true because if u don't have a valid license when operating a vehicle and you get pulled over you will get in trouble i know this because my parents got in trouble for it once

5 0
3 years ago
Under the right conditions, it is possible, due to surface tension, to have metal objects float on water. Consider placing a sho
stiv31 [10]

Answer:

D = 0.060732 in

Explanation:

given data

sp. wt. = 500 lb/ft³

diameter = 0.036 in

solution

we get here maximum diameter of rod that is express as

D = \sqrt{\frac{8 \sigma }{\pi y}}   ......................1

here \sigma surface tension of water at 60⁰f  = 5.03 × 10^{-3}  lb/ft and y = 500 lb/ft³

so put here value and we will get

D = \sqrt{\frac{8 \times 5.03 \times 10^{-3} }{\pi \times 500}}

D = 0.005061 ft

D = 0.060732 in

4 0
3 years ago
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