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ozzi
3 years ago
12

Q2) An engineer borrowed $3000 from the bank, payable in six equal end-of-year payments at 8%. The bank agreed to reduce the int

erest on the loan if interest rates declined in the United States before the loan was fully repaid. At the end of 3 years, at the time of the third payment, the bank agreed to reduce the interest rate from 8% to 7% on the remaining debt. What was the amount of the equal annual end-of-year
payments for each of the first 3 years? What was the amount of the equal annual end-of-year payments for each of the last 3 years?
Engineering
1 answer:
tatyana61 [14]3 years ago
6 0
Answer is: $637.28; just did the math but i really don’t want to type it all out.
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What are the potential hazards relating to materials handling injuries?
Ann [662]

Answer:

it's says potential that something not moving.

incorrectly cutting ties or securing devices because

this is so dangerous thing I know because being electrocuted is here this for me.

8 0
3 years ago
Assume the availability of an existing class, ICalculator, that models an integer arithmetic calculator and contains: an instanc
shtirl [24]

We connect with computers through coding, often known as computer programming.

<h3>How to code?</h3>
  • We connect with computers through coding, often understood as computer programming.
  • Coding exists similar to writing a set of instructions because it instructs a machine what to do.
  • You can instruct computers what to do or how to behave much more quickly by learning to write code.

class ICalculator {

int currentValue;

int add(int value) {

this.currentValue = currentValue + value;

return currentValue;

}

int sub(int value) {

this.currentValue = currentValue - value;

return currentValue;

}

int mul(int value) {

this.currentValue = currentValue * value;

return currentValue;

}

int div(int value) {

this.currentValue = currentValue / value;

return currentValue;

}

}

public class ICalculator2 extends ICalculator {

int negate() {

if (currentValue != 0)

this.currentValue = -currentValue;

return currentValue;

}

public static void main(String[] args) {

ICalculator2 ic = new ICalculator2();

ic.currentValue=5;

System.out.println(ic.add(2));

System.out.println(ic.sub(5));

System.out.println(ic.mul(3));

System.out.println(ic.div(3));

System.out.println(ic.negate());

}

}

To learn more about code, refer to

brainly.com/question/22654163

#SPJ4

3 0
1 year ago
A 11-cm-diameter horizontal jet of water with a velocity of 40 m/s relative to the ground strikes a flat plate that is moving in
Reika [66]

Answer:

F = 8552.7N

Explanation:

We need first our values, that are,

V_{jet} = 40m/s\\V_{Plate} = 10m/s \\D = 11cm

We start to calculate the relative velocity, that is,

V_r = V_{jet}-V_{plate}\\V_r = (40)-(10)\\V_r = 30m/s

With the relative velocity we can calculate the mass flow rate, given by,

\dot{m}_r = \rho A V_r

\dot{m}_r = (1000)(30) \frac{\pi (0.11)^2}{4}

\dot{m}_r = 285.09kg/s

We need to define the Force in the direction of the flow,

\sum\vec{F} = \sum_{out} \beta\dot{m}\vec{V} - \sum_{in} \beta\dot{m} \vec{V}\\

F = \dot{m}V_r

F = (285.09Kg/s)(30)

F = 8552.7N

8 0
3 years ago
What does it mean to say that PEER is a data-driven, consumer-centric, and comprehensive system?
Reika [66]

Answer:

have you heard of gnoogle?

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3 0
3 years ago
Read 2 more answers
assume a five layer network model. There are 700 bytes of application data. There is a 20 bye header at the transport layer, a 2
amm1812

Answer: The overhead percentage is 7.7%.

Explanation:

We call overhead, to all those bytes that are delivered to the physical layer, that don't carry real data.

We are told that we have 700 bytes of application data, so all the other bytes are simply overhead, i.e. , 58 bytes composed by the transport layer header, the network layer header, the 14 byte header at the data link layer and the 4 byte trailer at the data link layer.

So, in order to assess the overhead percentage, we divide the overhead bytes between the total quantity of bytes sent to the physical layer, as follows:

OH % = (58 / 758) * 100 = 7.7 %

4 0
2 years ago
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