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Sati [7]
2 years ago
9

What is the effect of the author proposing a "thought experiment" at the beginning of the text? FINANCIAL LITERACY

Physics
1 answer:
mojhsa [17]2 years ago
4 0

A thought experiment aims to promote speculative thinking, logical reasoning, and paradigm shifts. Thought experiments force us to address problems we find difficult to answer, which forces us out of our comfort zone. They highlight knowledge gaps and aid in recognizing the boundaries of what is knowable.

<h3>What are thought experiments?</h3>

Thought experiments are imaginative methods for examining the nature of things. They are employed for a variety of purposes in a number of disciplines, including physics, economics, history, mathematics, and philosophy.

A thought experiment is a test that we do in our minds. Here, we will imagine a specific scenario, consider some of its repercussions, and come to a broad conclusion.

Therefore, a thought experiment aims to promote speculative thinking, logical reasoning, and paradigm shifts. Thought experiments force us to address problems we find difficult to answer, which forces us out of our comfort zone. They highlight knowledge gaps and aid in recognizing the boundaries of what is knowable.

Learn more about experiments on:

brainly.com/question/17274244

#SPJ1

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Which has greater kinetic energy, a car traveling at 40 mph or a half-as-massive car traveling at 80 mph?
ziro4ka [17]

Answer:

The 80 mph car

Because the formula says 1/2 mass but for the velocity it is squared

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A racquetball strikes a wall with a speed of 30 m/s and rebounds in the opposite direction with a speed of 26 m/s. The collision
Fudgin [204]

Answer:

The average acceleration of the ball during the collision with the wall is a=2,800m/s^{2}

Explanation:

<u>Known Data</u>

We will asume initial speed has a negative direction, v_{i}=-30m/s, final speed has a positive direction, v_{f}=26m/s, \Delta t=20ms=0.020s and mass m_{b}.

<u>Initial momentum</u>

p_{i}=mv_{i}=(-30m/s)(m_{b})=-30m_{b}\ m/s

<u>final momentum</u>

p_{f}=mv_{f}=(26m/s)(m_{b})=26m_{b}\ m/s

<u>Impulse</u>

I=\Delta p=p_{f}-p_{i}=26m_{b}\ m/s-(-30m_{b}\ m/s)=56m_{b}\ m/s

<u>Average Force</u>

F=\frac{\Delta p}{\Delta t} =\frac{56m_{b}\ m/s}{0.020s} =2800m_{b} \ m/s^{2}

<u>Average acceleration</u>

F=ma, so a=\frac{F}{m_{b}}.

Therefore, a=\frac{2800m_{b} \ m/s^{2}}{m_{b}} =2800m/s^{2}

8 0
3 years ago
A vertical spring stretches 4.0 cm when a 12-g object is hung from it. The object is replaced with a block of mass 28 g that osc
marin [14]

Answer:

Time period of the osculation will be 0.0671 sec  

Explanation:

It is given a vertical spring is stretched by 4 cm

So change in length of the spring x = 4 cm = 0.04 m

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So kx=mg

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Now new mass is m = 28 gram = 0.028 kg

So time period with new mass will be

T=2\pi \sqrt{\frac{m}{k}}

=2\times 3.14 \sqrt{\frac{0.028}{244.7}}=0.0671sec

4 0
3 years ago
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