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Natali5045456 [20]
3 years ago
7

What type of reaction is shown in the following chemical equation: 2H2O → 2H2 + O2?

Physics
2 answers:
Kay [80]3 years ago
4 0

Answer:

Decomposition

Explanation:

A reaction in which one compound breaks up into two or more compounds is called a decomposition reaction.

atroni [7]3 years ago
4 0

Answer:

It is a decomposition reaction.

Explanation:

In a decomposition reaction, a single substance breaks down or breaks down, producing two or more different substances. In other words, decomposition reactions are those that form two or more substances from a compound. In this reaction the atoms that form a compound are separated to give the products according to the formula:

AB → A + B

This type of reactions can occur spontaneously or caused by certain external factors, such as heat.

In this case, you will see that the H₂O molecule decomposes to form two substances: H₂ and O₂.  Then you will see that it is a decomposition reaction.

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A person is wandering in woods and records his movements as a sequence of displacements: d1 is 351 m, 35.0° north of east; d2 is
Deffense [45]

Answer:

18.64

Explanation:

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When it comes to how ray lines are drawn, what makes the convex lens and concave mirror similar to each other?
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Answer:

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3 years ago
A 3.35 kg object initially moving in the positive x direction with a velocity of 4.90 m s collides with and sticks to a 1.88 kg
ahrayia [7]

Answer:

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Explanation:

Given;

mass of the first object, m₁ = 3.35 kg

initial velocity of the first object, u₁ = 4.90 m/s in positive x-direction

mass of the second object, m₂ = 1.88 kg

initial velocity of the second object, u₂ = 3.12 m/s in negative y-direction

initial momentum of the first object, P₁ = 3.35 x 4.9 = 16.415 kgm/s

initial momentum of the second object, P₂ = 1.88 x 3.12 = 5.8656 kgm/s

The resultant velocity of the two objects is given by;

R² = 16.415² + 5.8656²

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R = 17.432 kgm/s

Apply the principle of conservation of linear momentum for inelastic collision;

total initial momentum before = total final momentum after collision

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R = Pf

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17.432 = v(m₁ + m₂)

where;

v is the final components of velocity of the composite object

v = \frac{17.432}{m_1 + m_2} \\\\v = \frac{17.432}{3.35+1.88} \\\\v = 3.33 \ m/s

Therefore, the final components of velocity of the composite object is 3.33 m/s.

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2 years ago
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