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3 years ago

What type of reaction is shown in the following chemical equation: 2H2O → 2H2 + O2?

Physics

2 answers:

Kay [80]3 years ago

4 0

Answer:

Decomposition

Explanation:

A reaction in which one compound breaks up into two or more compounds is called a decomposition reaction.

atroni [7]3 years ago

4 0

Answer:

It is a decomposition reaction.

Explanation:

In a decomposition reaction, a single substance breaks down or breaks down, producing two or more different substances. In other words, decomposition reactions are those that form two or more substances from a compound. In this reaction the atoms that form a compound are separated to give the products according to the formula:

AB → A + B

This type of reactions can occur spontaneously or caused by certain external factors, such as heat.

In this case, you will see that the H₂O molecule decomposes to form two substances: H₂ and O₂. Then you will see that it is a decomposition reaction.

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Use the dot product to find the magnitude of u if u = 6i - 3j

LuckyWell [14K]

Vector u :
u = 6 i - 3 j
The magnitude of vector u :
| u | = $\sqrt{6 ^{2}+(-3) ^{2} } = \sqrt{36+9}= \\ \sqrt{45}= \sqrt{9*5}=3 \sqrt{5}$
Answer:
The magnitude of vector u is 3√5.

3 0

3 years ago

.A particle starts on the origin. It is pushed back to -5.7 m in 2.1 s. Then it is pushed

harina [27]

Answer: The average velocity is -0.965m/s

Explanation: The first step is to calculate the two velocities is both directions. A velocity is a distance per unit time.

V=d/ t

=-5.7/2.1

=-2.7m/s

For the other direction the velocity is

V=7.3/9.5

=0.77m/s

The average velocity the add the velocities and divide them by 2.

V=-2.7+0.77/2

V= 0.965m/s

5 0

3 years ago

Read 2 more answers

An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above

Lilit [14]

The length of its image = $-3cm$

Given,

length of object, $h_o = 3 cm$

We know, for flat refracting surface,

Image distance = object distance

So,

magnification is = $-1$

length of the image,

$h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm$

Here, negative sign means inverted image.

For more information on refraction, visit

brainly.com/question/14760207?referrer=searchResults

3 0

3 years ago

Q1. In a 100m track event, the time taken by four runners is 10 sec., 10.2 sec., 10.4 sec and 10.6 sec. Find the ratio of their

Anna35 [415]

Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v= $\frac{s}{t}$
we get
V₁= $\frac{100}{10}$
V₁=10m/s

V₂= $\frac{100}{10.2}$
V₂=9.8m/s

V₃= $\frac{100}{10.4}$
V₃=9.61 m/s

V₄= $\frac{100}{10.6}$
V₄=9.43 m/s

V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43

8 0

3 years ago

Projectile Motion: A hobbyist launches a projectile from ground level on a horizontal plain. It reaches a maximum height of 72.3

marin [14]

Answer:

The angle of launch from the horizontal direction is 20.99° .

Explanation:

Let u and θ be the initial speed and angle of projection from the horizontal axis of the object respectively.

The equations for projectile motion are :

H = ( u² sin²θ)/ 2g ......(1)

Here H is maximum height of the projectile motion and g is acceleration due to gravity.

R = ( u² sin2θ)/g .......(2)

Here R is the maximum horizontal displacement of the object.

Rearrange equation (1) in terms of u².

u² = (2gH)/sin²θ

Substitute this equation in equation (2).

R = (2gH sin2θ) / (sin²θ x g)

R = (2H sin2θ)/sin²θ

Using trigonometry property, sin2θ = 2 cosθ sinθ

So, above equation becomes,

R = (2H x 2 cosθ sinθ)/sin²θ

R = (4H cosθ)/sinθ

tanθ = R/4H

θ = tan⁻¹(R/4H)

Substitute 111 m for R and 72.3 m for H in the above equation.

θ = tan⁻¹( 111/ 4 x 72.3 )

θ = tan⁻¹(0.38)

θ = 20.99°

3 0

3 years ago