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Klio2033 [76]
1 year ago
13

Consider the following types of electromagnetic radiation:

Chemistry
1 answer:
maria [59]1 year ago
4 0

Electromagnetic radiation in increasing energy order:-

X-ray >Ultraviolet > Visible > Infrared >Microwave > Radio waves

<h3>Electromagnetic waves</h3>

The energy transfer technique is the use of electromagnetic waves. They are created when a fluctuating magnetic field causes a fluctuating electric field. These induced, perpendicularly oscillating electric and magnetic forces are what make up electromagnetic waves. Electromagnetic waves can travel without a medium, in contrast to mechanical waves. Therefore, even in the absence of a medium, electromagnetic waves can pass through a vacuum. Radio waves, microwaves, infrared waves, visible light, ultraviolet light, X-rays, and gamma rays are all examples of electromagnetic waves

Electromagnetic wave                 Wavelength

(1) Microwave                   =           1 mm to 0.1 m

(2) Ultraviolet                    =              10 nm to 400 nm

(3) Radio waves          =                 1 mm to 100 km

(4) Infrared                   =                 700 nm to 1 mm

(5) X-ray                     =                0.01 nm to 10 nm

(6) Visible                   =               400 nm to 700 nm

Learn more about Electromagnetic waves here:-

brainly.com/question/894752#SPJ4

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Notice that the effective analytical connection for analysis of hypochlorite anion by the thiosulfate anion in this experiment i
hoa [83]

Answer:

b. Two moles of thiosulfate anion needed to react with one mole of hypochlorite anion.

Explanation:

1. Hypochlorite with iodide

                      2I⁻ ⟶ I₂ + 2e⁻

<u>ClO⁻ + 2H⁺ + 2e⁻ ⟶ Cl⁻ + H₂O      </u>

2I⁻ + ClO⁻ + 2H⁺ ⟶ I₂  + Cl⁻ + H₂O

2. Thiosulfate with iodine

     2S₂O₃²⁻ ⟶ S₄O₆²⁻ + 2e⁻

<u>       I₂ + 2e⁻ ⟶ 2I⁻               </u>    

2S₂O₃²⁻ + I₂ ⟶ S₄O₆²⁻ + 2I⁻

3. Sum of the reactions

                2I⁻ + ClO⁻ + 2H⁺ ⟶ I₂  + Cl⁻ + H₂O

<u>                       2S₂O₃²⁻ + I₂ ⟶ S₄O₆²⁻ + 2I⁻                    </u>

2I⁻ + ClO⁻ + 2S₂O₃²⁻ + 2H⁺ ⟶ I₂  + Cl⁻ + S₄O₆²⁻ + H₂O

4. Molar ratio

S₂O₃²⁻:ClO⁻ = 2:1

7 0
3 years ago
Apresentando a configuração eletrônica 1s2 2s2 2p6 3s2 3p4 um determinado elemento químico se mostra com forte tendência para:
Bess [88]

Answer:

E

Explanation:

To know what will happen, we need to know

the total number of electrons the element have.

This can be calculated by adding all the electrons together

That would be 2 + 2 + 6 + 2 + 4 = 16

This shows that the element is sulphur.

Now using the KLMN electronic configuration, sulphur has the shells 2,8,6 meaning there are 2 extra electrons needed for octet configuration to be achieved.

This makes option E the correct answer to the question

6 0
3 years ago
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