Answer:
Two factors that might have a affect of which copper sulphate mineral will occur at a given location is:
A. Copper sulphate high solubility in water
B. Also it binds nicely with the sediments or the crystal.
Explanation:
As it is mentioned here that copper sulphate can be crystallized as an anhydrate which means that their is no waterin those crystals or can be as of those three different hydrates whose crystal structure varies with the amount of water present in it.
The four forms are also given of the copper sulphate are:
- Bonatite
- Boothite
- Chalcanthite
- Chalcocyanite
So, the two factors that might give an affect which type of copper sulphate mineral willoccur at a given location is:
A. The copper sulphate high solubility in water.
B. It binds extremely nicely with the sediments or say to the crystal. It is also regulated by plants.
The symbol of the period five element that is a member of the pnicitides family are antimony.
Explanation:
Pnictogen family
- In periodic table, column 15 elements are Pnitogen family.
- The pnictogen elements are Nitrogen-N, arsenic-As, phosphorus-P, bismuth-Bi, antimony-Sb, ununpentium-Uup.
- There are five valence electrons each member of pnictogen family. In group 15 double bonds and triple bonds are formed due to these valence electrons.
- Pnictides, binary compounds of group 15.
Antimony
- Antimony is the element found in period 5 and block p.
- A chemical element, Antimony (Sb) from Latin word stibium and 51 is its atomic number. It is in solid state.
- In ancient times, antimony compounds are used as cosmetic and medicine.
- Appeared as semi metal.
- Electronic configurations of Sb is [Kr] 4d105s25p3.
Assuming that you’re looking for the concentration of water in the solution, then it would be 0.028 M.
You would have to use the formula:
c1v1 = c2v2, where c =concentration and
v = volume
C1 = ?
V1 = 250 mL
C2 = 0.2 M
V2 = 35 mL
C1 x 250 mL = 0.2 M x 35 mL
C1 = (0.2 M x 35 mL) / 250 mL
C1 = 0.028 M of water added to 35mL of 0.2M HCl
Therefore, there is 0.028 M of water added to 35mL of 0.2M HCl
Answer:
is reduced in the reaction
Explanation:
The given reaction is
The oxidation number of 
is changed from 
And The oxidation number of 
is changed from 
Hence, 
is oxidized and is reduced
