Answer:
The temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C
Explanation:
Here we make use of the Clausius-Clapeyron equation;
Where:
P₁ = 1 atm =The substance vapor pressure at temperature T₁ = 282°C = 555.15 K
P₂ = 0.2 atm = The substance vapor pressure at temperature T₂
= The heat of vaporization = 28.5 kJ/mol
R = The universal gas constant = 8.314 J/K·mol
Plugging in the above values in the Clausius-Clapeyron equation, we have;
T₂ = 440.37 K
To convert to Celsius degree temperature, we subtract 273.15 as follows
T₂ in °C = 440.37 - 273.15 = 167.22 °C
Therefore, the temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C.
Someone’s initials i think
The c of the water or specific heat of water is 4 if the temperature is 25 degrees c and cubic meter in air. Contain 22 grams
Oxygen to sulfur is less polar than comparable bonds to oxygen because sulfur is less electronegative than oxygen.
In groups, electronegativity rises from bottom to top; across periods, it rises from left to right. In groups, electronegativity rises from bottom to top; across periods, it rises from left to right. Fluorine is the element with the greatest electronegative charge, whereas francium has a very low electronegative charge. Within a set of elements, electronegativity values drop from top to bottom. Moving from left to right along a period improves electronegativity. This is caused by a decrease in atomic size and a rise in nuclear charge, which allows a shared electron pair to be more attracted to one another.
Learn more about Electronegativity here-
brainly.com/question/17762711
#SPJ4
