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mamaluj [8]
2 years ago
11

A solution is 40 cetic acid by mass. the density of this solution is 1.049 g/ml. Calculate the mass of pure acetic acid in 220 m

l of this solution at 20C. answer in units of g.
Chemistry
1 answer:
taurus [48]2 years ago
7 0

The mass of pure acetic acid in 220 ml of the given solution at 20°C is 92.311 g

<h3>What is Acetic acid?</h3>

Acetic acid is a type of carboxylic acid and also known as ethanoic acid

Its formula is CH₃COOH.

It is an organic compound and is a colorless liquid

It is mostly used in the production of vinegar

40 % acetic acid by mass means,

40 g of acetic acid is dissolved in 100 g of solution.

The density of solution at 20°C,

\rho = 1.049 g/ml

We know,

\rho = \frac{m}{V}

V = \frac{m}{\rho}

The volume of the solution, V = \frac{100}{1.049} = 95.33 ml

95.33 ml of solution contains 40 g of pure Acetic acid

220 ml of solution contains\frac{40 \times 220}{95.33} = 92.311 g of pure Acetic acid

Thus, the mass of pure Acetic acid in 220 ml of solution at 20°C is 92.311 g

Learn more about acetic acid:

brainly.com/question/24304533

#SPJ4

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Alpha decay process is the process in which nucleus of an atom disintegrates into two particles. The first one which is the alpha particle consists of two protons and two neutrons. This is also known as helium nucleus. The second particle is the daughter nuclei which is the original nucleus minus the alpha particle released.

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The nuclear equation for this process follows:

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<u>For B:</u> Plutonium-239 emits an alpha particle

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<u>For C:</u> Thorium-239 emits a beta particle

The nuclear equation for this process follows:

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