- The wavelength range of Infrared radiation is 700 nanometers to 1 millimeter.
- The sun emits mainly near-infrared which is mainly composed of wavelength below 4 micrometers.
- The thermal range of infrared ranges between wavelengths 3.5 and 2.0 micrometers
Explanation:
The wavelength range of Infrared radiation is 700 nanometers to 1 millimeter. This also translates to a frequency range of 430 TeraHertz to 300 Giga Hertz.
Because the sun is a star and is hot in comparison to earth and other planetary bodies, the bigger range of infrared radiation it emits is in the near-infrared which is mainly composed of wavelength below 4 micrometers.
The earth's surface produces infrared radiation of the mid-infrared range while cooler substances will produce far-infrared range
The thermal range of infrared ranges between wavelengths 3.5 and 2.0 micrometers and is produced by black bodies.
Learn More:
For more on infrared radiation check out;
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<span>The pH is given by the Henderson - Hasselbalch equation:
pH = pKa + log([A-]/[HA])
pH = -log(</span><span>1.3 x 10^-5) + log(0.50/0.40)
pH = 4.98
The answer to this question is 4.98.
</span>
Answer:
b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)
Explanation:
The equation is given as;
2HCl(aq) + Zn(s) + H2(g) + ZnCl2(aq)
In writing an ionic equation, only the aqueous compounds dissociates into ions. This means HCl and ZnCl2 would dissociate to form ions.
This is given as;
2H+ + 2Cl- + Zn(s) --> H2(g) + Zn2+ + 2Cl-
The correct option is;
b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)
c is the answer a benzene
The fructose chemical formula is C6H12O6. The answer to the question above regarding the major species present when fructose is dissolved in water (H2O) is "None". No ions are present. It is false that when sugar is dissolved in water there will be strong electrolytes.
