Question

Calculate the volume in ml of hydrogen gas at stp produced when 25.0 g of zn metal reacted completely with excess of h2so4.

Answer 1

The volume of hydrogen gas produced from the reaction at STP is 8517.32 mL.

Volume is a measure of occupied 3-dimensional space. Its miles are often quantified numerically using SI-derived gadgets or with the aid of various imperial devices. The definition of length is interrelated with the extent.

Volume is the amount of 3-dimensional space occupied by means of a liquid, strong, or gas. commonplace devices used for specific quantities include liters, cubic meters, gallons, milliliters, teaspoons, and ounces, even though many different units exist.

Volume is the measure of the ability that an object holds. as instance, if a cup can hold 100 ml of water up to the brim, its extent is stated to be one hundred ml. volume can also be described as the amount of space occupied by a 3-dimensional object.

The given reaction can be written as,

Zn + H2SO4 ZnSO4 + H2

Mass of Zn = 65.38 g/mol

Mass of H = 1 g/mol

Mass of H2= 2 g/mol

From this equation, one mole or 65.38 g of Zn produces 2 g of H2.

Thus 25 g of Zn produce,

25×2/65.38 = 0.76g of $H_{2}$

One mole of H2 is 2 g,

Therefore no.of moles of .76 g H2 is,

0.76/2 = 0.38 moles

one mole of H2 contains 22414 mL of volume at STP.

Therefore volume occupied by 0.38 moles is,

0.38×22414 = 8517.32ml

Thereby volume of hydrogen gas produced from the reaction at STP is 8517.32 mL.

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