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olya-2409 [2.1K]
2 years ago
15

Three identical 6.67-kg masses hang at rest from three identical springs, numbered as in the figure. Each spring has an unstretc

hed length of 0.23 m and a spring constant of 8.13 kN/m. How long, L , is spring 2?
[Hint: Draw some FBDs and apply Newton's second law. Remember to account for both the spring's stretch and its unstretched length.]

Physics
1 answer:
Karolina [17]2 years ago
5 0

The length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.

<h3>Extension of the spring 2</h3>

The extension of the spring 2 is determined from the net force acting on spring 2.

F(net) = Kx

<em>Net force on spring 2 = sum of forces acting downwards - sum of forces acting upwards.</em>

Net force on spring 2 = (force on 2 + force on 3) - (force on 1)

F(net) = (m₂ + m₃)g - (m₁)g

F(net) = (6.67 + 6.67)9.8  -  (6.67)9.8

F(net) = 130.732 - 65.366

F(net) = 65.366 N

x = F/k

x = (65.366)/(8130)

x = 0.00804 m

The length of spring 2 = x + 0.23 m

                                     = 0.00804 m + 0.23 m = 0.238 m

Thus, the length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.

Learn more about extension of elastic material here: brainly.com/question/26838571

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Feel better and develop communication skills

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6 0
2 years ago
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 78.5 m/s. Th
Andrews [41]

Answer:

FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

Explanation:

First you have to consider that the Ford Thunderbird (FT) follows a rectilinear motion with varying acceleration, while Mercedez Benz (MB) has a constant velocity (no acceleration). So if you finde the time spent by FT in each section, and the distance, then you will find the distance for MB.

1) Vf² = Vi² + 2ad, where Vf: final velocity, Vi: ionitial velocity, a: acceleration and d: distance.

For the first portion  (0 m/s)² = (78.5 m/s)² + 2a(250 m) ⇒

-(78.5 m/s)² / 2(250m) = a ⇒ a = -12.3 m/s².

Now, you can find the corresponding time for this section with the following formule: Vf = Vi + at ⇒ 0 m/s = 78.5 m/s + (-12.3 m/s²) t

⇒ t= (-78.5 m/s)/ (-12.3 m/s²) ⇒ t= 6.4 seconds.

2) Then FT spent 5 seconds in the pit.

3) The the FT accelerates until reach 78.5 m/s again in a distance of 370 m.

Vf² = Vi² + 2ad ⇒ (78.5 m/s)² = (0 m/s)² + 2a(370 m)

⇒ (78.5 m/s)²/ 2(370 m) = a ⇒ a = 8.3 m/s²

Then, Vf = Vi + at ⇒ 78.5 m/s = 0 m/2 + (8.3 m/s²) t

⇒ (78.5 m/s)/(8.3 m/s²) = t ⇒ t = 9.5 seconds.

4) Summarizing, the FT moves 620 meters (250 + 370 mts) in 20.9 seconds ( 6.4 s + 5 s + 9.5 s).

5) During this time, MB moves

Velocity = distance/ time ⇒ Velocity x time = Distance

⇒ Distance = (78.5 m/s) x  (20.9 seconds) ⇒ Distance = 1640.6 meters

6) Finally, the FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

3 0
3 years ago
the goat weighs 900 N and is 1 meter from the fulcrum. The strongman pulls down on the lever 3 meters from the fulcrum. What is
garik1379 [7]

Answer: The smallest effort = 300N

Explanation:

Using one of the condition for the attainment of equilibrium:

Clockwise moment = anticlockwise moments

900 × 1 = 3 × M

Where M = the weight of the strong man

3M = 900

M = 900/3 = 300N

Therefore, 300N is the smallest effort that the strongman can use to lift the goat

6 0
3 years ago
How Many Negative (-) Electrons are there
makvit [3.9K]

Answer:

All electrons are negative(-) charged

5 0
2 years ago
What is the principle of potentiometer?​
kupik [55]

Answer:

The principle of a potentiometer is that the potential dropped across a segment of a wire of uniform cross-section carrying a constant current is directly proportional to its length. The potentiometer is a simple device used to measure the electrical potentials (or compare the e.m.f of a cell).

Explanation:

I hope it will help you

6 0
3 years ago
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