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Romashka-Z-Leto [24]
3 years ago
14

A construction worker runs a jack hammer for 1.5 hours. The jack hammer has 2.4 kilowatts of power. How much electrical energy d

oes the construction worker use running the jack hammer?
A. 3.6 kilowatt-hours

B. 3600 kilowatt-hours

C. 0.625 kilowatt-hours

D. 1.6 kilowatt-hours
Physics
1 answer:
scoray [572]3 years ago
8 0
Its a because 24*15 is 360 but you have to put the decimal back so its 3.6 kilowats per hour plz mark brainlest 
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Find the currents flowing in the circuit in the figure below. (Assume the resistances are
Nitella [24]

By Kirchoff's law in left side loop

E_1 + E_2 = {r_1 + R_1 + R_4)I_1 + (R_2 + r_2) I_3

similarly kirchoff's law in right side loop

E_3 - E_4 - E_2 = (r_3 + r_4 + R_3)I_2 - (R_2 + r_2)I_3

also by junction law we know that

I_1 = I_2 + I_3

now by plug in all values we have

18 + 3 = (0.5 + 8 + 15)I_1 + (10 + 0.25)I_3

21 = 23.5I_1 + 10.25I_3

12 - 24 - 3 = (0.75 + 0.25 + 12)I_2 - (10+ 0.25)I_3

-15 = 13I_2 - 10.25I_3

So by solving above equations we have

I_1 = 0.492 A

I_2 = -0.428 A

I_3 = 0.920 A

6 0
3 years ago
An ambulance is rapidly approaching you at a stop light. What happens to the frequency and pitch of the sound as the ambulance d
vagabundo [1.1K]

Answer:

A )

Explanation:

This change in frequency observation occur due to doppler effect

if the wave source moves,In the time between one wave peak being emitted and the next, the source will have moved so that the shells will no longer be concentric. The wavefronts will get closer together in front of the source as it travels and will be further apart behind it.  (see the graph)

when the person standing still in front of the ambulance, he will observe a <em>higher frequency </em>than before as the source travels towards them.

f_(observed)=\frac{V_(wave)}{V_(wave)-V_(source)} *f_(original)

The pitch we hear depends on the frequency of the sound wave.

A high frequency corresponds to a high pitch

as we hear a higher frequency , it makes the <em>pitch higher</em> too

5 0
3 years ago
Read 2 more answers
A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori
UNO [17]

Answer:

6.4 J

Explanation:

m = mass of the bullet = 10 g = 0.010 kg

v = initial velocity of bullet before collision = 1.8 km/s = 1800 m/s

v'  = final velocity of the bullet after collision = 1 km/s = 1000 m/s

M = mass of the block = 5 kg

V = initial velocity of block before collision = 0 m/s

V'  = final velocity of the block after collision = ?

Using conservation of momentum

mv + MV = mv' + MV'

(0.010) (1800) + (5) (0) = (0.010) (1000) + (5) V'

V' = 1.6 m/s

Kinetic energy of the block after the collision is given as

KE = (0.5) M V'²

KE = (0.5) (5) (1.6)²

KE = 6.4 J

4 0
4 years ago
According to our theory of solar system formation, why do all the planets orbit the Sun in the same direction and in nearly the
11Alexandr11 [23.1K]

The laws of conservation of energy and conservation of angular momentum ensure that any rotating, collapsing cloud will end up as a spinning disk is the reason.

<h3>What is an Orbit?</h3>

This is defined as a curved path in space which is characterized by an object going round and round a planet, moon, or star.

In this scenario, all the planets orbit the Sun in the same direction and in nearly the same plane to ensure any rotating, collapsing cloud will end up as a spinning disk.

Read more about Orbit here brainly.com/question/3668699

4 0
2 years ago
A .5kg football is thrown with a velocity of 15m/s to the right. A stationary receiver catch the bail and bring it to rest in 0.
storchak [24]
<h3>Answer:</h3>

375 N

<h3>Explanation:</h3>

Topic tested: Newton's Law of motion

The question is testing on the application of Newton's second Law of motion.

We are given;

  • Mass of the football = 5 Kg
  • Initial velocity of the football, Vf = 15 m/s
  • Time taken to bring the ball to rest = 0.2 s
  • Final velocity, Vo = 0 m/s ( since the ball went to rest)

We are required to determine the force exerted to bring it to rest.

  • According to the Newton's second law of motion the resultant force and rate of change in momentum are directly proportion.
  • Therefore;

F=\frac{(MVf-MVo)}{t}

Thus;

F=\frac{(5kg.5m/s)-(5kg.0m/s)}{0.2s}

F=375Newtons

Force = 375 N

Hence, the force exerted on the ball by the receiver was 375 N

5 0
3 years ago
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