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tekilochka [14]
3 years ago
15

Question 3. AP PHYSICS. Currently learning about torque so I assume you apply torque. I don't get it at all

Physics
1 answer:
8090 [49]3 years ago
8 0

wow that is confusing


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two bowling balls each have a mass of 8kg. if they are 2 m apart, what is the gravitational force between them?
Scilla [17]

Answer:

1 x 10^-9 N

Explanation:

F = Gm²/d² = 6.674e-11(8²)/2² = 1.06784e-9

4 0
3 years ago
Calculate the kinetic energy, in joules of a 1160-kg automobile moving at 19.0 m/s.
Rudiy27

Answer:

Explanation:

K.E=1/2 mv²

m=1160 kg

v=19.0 m/s

so k.e=1/2*1160*(19.0)²

K.E=1/2*1160*361

K.E=1/2*418760

K.E=209380=2.0*10^5 j

7 0
3 years ago
Define 1 joule work ?​
Nina [5.8K]

Explanation:

Force is applied to lift a body against the force of gravity. Example: If an object is lifted to a certain height (h)

4 0
2 years ago
Which statement accurately describes science?
slava [35]
Answer: We don’t really ever need to know how to dissect a frog but hey, one day maybe I’ll need to give a frog a discectomy
5 0
3 years ago
A 23.5 g piece of aluminum metal is initially at 100.0°C. It is dropped into a coffee cup-calorimeter containing 130.0 g of wate
vivado [14]

Answer: The molar heat capacity of aluminum is 25.3J/mol^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of water = 130.0 g

m_2 = mass of aluminiunm = 23.5 g

T_{final} = final temperature = 26.0^oC=(273+26)K=299K

T_1 = temperature of water = 23^oC=(273+23)K=296K

T_2 = temperature of aluminium = 100^oC=273+100=373K

c_1 = specific heat of water= 4.184J/g^0C

c_2 = specific heat of aluminium= ?

Now put all the given values in equation (1), we get

130.0\times 4.184\times (299-296)=-[23.5\times c_2\times (299-373)]

c_2=0.938J/g^0C

Molar mass of Aluminium = 27 g/mol

Thus molar heat capacity =0.938J/g^0C\times 27g/mol=25.3J/mol^0C

5 0
3 years ago
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