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tekilochka [14]
3 years ago
15

Question 3. AP PHYSICS. Currently learning about torque so I assume you apply torque. I don't get it at all

Physics
1 answer:
8090 [49]3 years ago
8 0

wow that is confusing


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A car passes point “A” and then 120 meters later. It’s velocity was measured 21 m/s. If it’s acceleration was constant at 0.853
Norma-Jean [14]

Recall that

{v_f}^2-{v_i}^2=2a\Delta x

where v_i and v_f are the initial and final velocities, respecitvely; a is the acceleration; and \Delta x is the change in position.

So we have

\left(21\dfrac{\rm m}{\rm s}\right)^2-{v_i}^2=2\left(0.853\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)

\implies v_i\approx\boxed{15.4\dfrac{\rm m}{\rm s}}

(Normally, this equation has two solutions, but we omit the negative one because the car is moving in one direction.)

7 0
3 years ago
Why is it important that two different metals are used in building an electrochemic<br> cell?
Mnenie [13.5K]

Answer:

Explanation:

They need a galvanic difference. Or saying that less technically,  they need to have different electron attraction, so that one can collect electrons (oxidation/reduction)  and flow current from the other.  :)

5 0
3 years ago
What did Charles Darwin’s conclude on the Galapagos Island? Plz answer fast
kvasek [131]
He discovered several species of finches that varied from island to island and it helped him make his theory of natural selection.

hope this helps ! 
3 0
3 years ago
What does convection mean
Sladkaya [172]
Convection is the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat
4 0
3 years ago
These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the neg
Kay [80]

Answer:

Following are the solution to the given question:

Explanation:

For charging plates that are connected in a similar manner:

Calculating the total charge:

\to q =q_1 + q_2 = C_1V_1 +C_2V_2 =1320 + 2714 = 4034 \mu C

Calculating the common potential:

\to V = \frac{q}{C}= \frac{q}{(C_1 + C_2)} =\frac{4034}{6.8} = 593 \ V\\\\

Calculating the charge after redistribution:

When: \\\\q = q_{1}' + q_{2}' = q_1 + q_2        

\to q_{1}' = C_1V = 2.2 \times 593 = 1305\ \mu C\\  \\  \to               q_{2}' = C_2V = 4.6 \times 593 = 2729 \ \mu C

6 0
3 years ago
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