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bulgar [2K]
3 years ago
10

Simplify -2/3 - 3/5 A) -1/15 B) -19/15 C) -3/5 D) -5/8

Physics
1 answer:
Leto [7]3 years ago
7 0
I got B,when you subtract 3/5 from NEGATIVE 2/3 it creates a negative 19 over a positive 15.

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Collaborative learning focuses on the learning of an individual. True or False
Jobisdone [24]

Answer:

False

Explanation:

The collaborative learning is not a type of learning that focuses on individual learning. This type of learning focuses on joint learning between two or more individuals that act as a team. The collaborative learning is a method that encourages the two or more individuals to work together, to capitalize on each other's skills and resources for the benefit of the whole, for the team. This type of learning has its own supporters and critics, as some consider it as excellent way to develop the team work and closer bonds between the people, while others argue that it is destroying the potential of the individual.

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4 years ago
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2. Use the data table below to respond to the
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car d

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Claire rides her scooter to school, traveling 25 km/h. How much time in minutes does it take her to travel to her school, which
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3 years ago
Determine the speed of an object moving at 35 seconds over a distance at 472.5 meters
Jlenok [28]

Answer:

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v = b*l*h

472.5 = 7*3*length

(rearranging the equation)

length = 472.5/21

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6 0
3 years ago
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1. The strength coefficient and strain-hardening exponent of brass are 100,000 lb/in2 and 0.35 respectively. A cylindrical speci
aleksandr82 [10.1K]

To solve this problem we will apply the concepts of strain, flow stress and average flow stress to find the required data. We will start by calculating the Strain which is the logarithmic relationship between the longitudinal change. Later we will find the flow stress through the strength coefficient, the strain and the strain-hardening exponent. Finally with the found values it will be possible to find the average flow stress,

Now the strain is calculated with the logaritmic relation of the lengths.

\epsilon = ln(\frac{1.5}{3.0})

\epsilon = ln(0.5)

\epsilon = 0.69315in/in

With this value we can calculate the flow stress,

Y_f = K\epsilon^n

Here,

K = Strneght coefficient

n = Strainhardening exponent of brass

Y_f = (100000)(0.69315)^{0.35}

Y_f = 87961lb/in^2

Finally the average flow stress will be given under the relation:

\bar{Y_f} = \frac{K\epsilon^n}{1+n}

\bar{Y_f} = \frac{(100000)(0.69315)^{0.35}}{1.35}

\bar{Y_f} = 65156lb/in^2

6 0
3 years ago
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