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slava [35]
2 years ago
6

A glow stick contains a glass vial with chemicals. when the glow stick is bent, the vial breaks and the chemicals react to produ

ce a glow. a science student observes that a glow stick kept in the freezer glows for a longer duration than a glow stick kept at room temperature. what conclusion can be drawn based on the observation? be sure to note the outcome and test variables in the conclusion.
Chemistry
1 answer:
mina [271]2 years ago
6 0

A glow stick will glow longer at lower temperatures than at room temperature, one can infer from the observation. Temperature and reaction time are the test variables.

We notice in this reaction that a glow stick stored in the freezer lights for a longer period of time than a glow stick stored at normal temperature. This implies that temperature affects how long a response lasts.

The most straightforward explanation for this observation is that glow sticks glow longer in colder temperatures than they do at room temperature; as a result, glow sticks kept in the freezer are observed to glow longer than glow sticks kept at room temperature.

To learn more about chemicals to the given link:

brainly.com/question/24600141

#SPJ4

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Jose and Sarah are running in the cross country meet. Their skeletal and muscular systems work to move them through the course.
Inessa [10]

Answer: Jose and Sarah are running in the cross country meet. Their skeletal and muscular systems work to move them through the course. As they run, they breathe faster and harder and their heart rate increases.

A.work together

Explanation:This should help:)

5 0
3 years ago
For the balanced chemical reaction
musickatia [10]

Answer:

150

Explanation:

  • C₄H₂OH + 6O2 → 4CO2 + 5H₂O

We can <u>find the equivalent number of O₂ molecules for 100 molecules of CO₂</u> using a <em>conversion factor containing the stoichiometric coefficients of the balanced reaction</em>, as follows:

  • 100 molecules CO₂ * \frac{6moleculesO_2}{4moleculesCO_2} = 150 molecules O₂

150 molecules of O₂ would produce 100 molecules of CO₂.

5 0
3 years ago
A 2.00 kg piece of lead at 40.0°C is placed in a very large quantity of water at 10.0°C,and thermal equilibrium is eventually re
sveticcg [70]

Answer:

Δ S = 26.2 J/K

Explanation:

The change in entropy can be calculated from the formula  -

Δ S = m Cp ln ( T₂ / T₁ )

Where ,

Δ S = change in entropy

m = mass  = 2.00 kg

Cp =specific heat of lead is 130 J / (kg ∙ K) .

T₂ = final temperature  10.0°C + 273 = 283 K

T₁ = initial temperature ,  40.0°C + 273 = 313 K

Applying the above formula ,

The change in entropy is calculated as ,

ΔS = m Cp ln ( T₂ / T₁ )  = (2.00 )( 130 ) ln( 283 K / 313 K )

ΔS = 26.2 J/K

6 0
3 years ago
Define shielding and effective nuclear charge. What is the connection between the two?
ivolga24 [154]

Answer:

The relation between the shielding and effective nuclear charge is given as

Z_{eff} = Z -S

where s denote shielding

z_{eff} denote effective nuclear charge

Z - atomic number

Explanation:

shielding is referred to as the repulsion of an outermost electron to the pull of electron from valence shell.  Higher the electron in valence shell higher will be the shielding effects.  

Effective nuclear charge is the amount of net positive charge that valence electron has.

The relation between the shielding and the effective nuclear charge is given as  

Z_{eff} = Z -S

wheres denote shielding

z_{eff} denote effective nuclear charge  

Z - atomic number

8 0
3 years ago
Guys what is valency in chemistry please I need help I will give brainlest pleaseeee help
Nutka1998 [239]

Answer:

the combining power of an element, especially as measured by the number of hydrogen atoms it can displace or combine with.

Explanation:

3 0
3 years ago
Read 2 more answers
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