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alex41 [277]
1 year ago
13

chegg why is a reaction with a negative GIbbs free enrgy always spontatous mor eenrgy is need to form the products thant the rea

ctants so energy must be added less energy is need to form the products than the amount of eneryg present in the reactants a nefative G
Chemistry
1 answer:
Svetach [21]1 year ago
3 0

A negative G indicates that there is more free energy in the reactants, or beginning state than in the products, or final state.

Exergonic reactions, which can take place without the supply of energy, are also known as spontaneous reactions.

Not all Gibbs's free energy is bad. Gibbs's free energy is negative for spontaneous reactions at a given temperature and positive for non-spontaneous reactions.

A spontaneous reaction is one that happens under specific circumstances without the addition of energy or outside influence. Since spontaneous reactions can happen rapidly or over the course of several days, months, or years, reaction spontaneity is independent of reaction rate.

Learn more about Gibbs's free energy it here ]brainly.com/question/23100006

#SPJ4.

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At 25°C, 100 g of water will be saturated with 35.7 g of NaCl. Which word below describes the solution of 1.55 mol of NaCl disso
erica [24]
1) The saturation point at 25°C is 35.7 g of NaCl / 100 g of water => 35.7 %

Under normal circumstances water will not accept more salt than that.

2) The solution with 1.55 mol of NaCl dissolved in 250 mL of water =>

molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

grams of NaCl = 1.55 mol * (molar mass of NaCl) = 1.55mol * 58.44 g/mol = 90.58 grams of NaCl


grams of water = 250 mL * 1 g/mL = 250 g/g.

Concentration of the solution:  [90.58 g NaCl / 250 g H2O] * 100 = 36.23 %

3) Conclusion: the solution has more salt than the saturation value. This means that the solution is supersaturated.

Supersaturation is a special condition, which is unstable, but that is not part of the questions.

The answer is supersaturated, 
5 0
4 years ago
QUICK I NEED THE ANSWER!! Compare the symmetry of an echinoderm to the symmetry of worms
Nikitich [7]

Answer:

C.Echinoderms have radial symmetry and worms have bilateral symmetry

Explanation:

Echinoderms evolved from animals with bilateral symmetry. The larvae of all echinoderms are bilaterally symmetrical but lost during metamorphosis  developing into radial symmetry adult. Examples of echinoderms are  starfish, sea urchins, sand dollars.

Worms are invertebrate animals having bilateral symmetry. They have a definite anterior (head) end and a posterior (tail) end. Worms have brains that help them detect objects, food,  mates, and predators quickly.

5 0
3 years ago
What are 3 methods you can use to separate a mixture? Give an example of each.
max2010maxim [7]

Answer:

The three methods we can use to separate a mixture are:

1.sublimation

example: sand and camphor

2.centrifugation

example:cream from milk

3.evaporation

example:salt from sea water

6 0
3 years ago
a geologist concludes that a rock sample is an extrusive igneous rock. Based on this information, which statement about the rock
katen-ka-za [31]

Answer: The rock formed from cooling lava.

Explanation:Extrusive igneous rocks, also known as volcanic rocks, are formed at the crust's surface as a result of the partial melting of rocks within the mantle and crust.

6 0
4 years ago
Nitrogen gas at 300 k and 200 kpa is throttled adiabatically to a pressure of 100 kpa if the change in kinetic energy is negligb
erastovalidia [21]

Answer:

The temperature of the Nitrogen after throttling is  T_2 = 300 \  K

Explanation:

From the question we are told that

   The  temperature is  T_1 =  300 \  K

    The pressure is  P =  200 \  kPa  =  200 * 10^{3} \  Pa

    The pressure after being  P_1 =  100 \  kPa =  100 * 10^{3} \  Pa

   

Generally from the first law of thermodynamics we have that

      Q - W =  \Delta U + \Delta  K

Here \Delta U  is the change internal  energy which is mathematically represented as

            \Delta U =  C_p  (T_2 - T_1)

Here      C_p is the specific heat of the gas at constant pressure

        \Delta K  is the change kinetic energy which is negligible

         Q  is the thermal  energy  which is Zero for an adiabatic process

         W  is the work done and the value is zero given that the gas was throttled adiabatically

So

      0=  \Delta U +0

=>   \Delta U  = 0

=>  (T_2 - 300)  = 0

=>   T_2 = 300 \  K

     

3 0
3 years ago
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