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Vlada [557]
3 years ago
12

Concentrated hydrochloric acid, HCl, comes with an approximate molar concentration of 12.1 M. If you are instructed to prepare 3

50.0 mL of a 0.975 M HCl solution, how many milliliters of the stock (concentrated) HCl solution will you use
Chemistry
1 answer:
Semmy [17]3 years ago
6 0

Answer:

28.20 mL of the stock solution.

Explanation:

Data obtained from the question include the following:

Molarity of stock solution (M1) = 12.1 M

Volume of diluted solution (V2) = 350.0 mL

Molarity of diluted solution (M2) = 0.975 M

Volume of stock solution needed (V1) =..?

The volume of stock solution needed can be obtained by using the dilution formula as shown below:

M1V1 = M2V2

12.1 x V1 = 0.975 x 350

Divide both side by 12.1

V1 = (0.975 x 350)/12.1

V1 = 28.20 mL.

Therefore, 28.20 mL of the stock solution will be needed to prepare 350.0 mL of 0.975 M HCl solution.

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Weight and mass are essentially the same measurements.<br> True or false?
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The answer to this question is False

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3 years ago
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What forms the biggest carbon reservoir on Earth?​
guajiro [1.7K]

Answer:

oceans is the answer that I got

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2 years ago
How many grams of water are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca
leva [86]

Answer:

The answer to your question is: 6.8 g of water

Explanation:

Data

2.6 moles of HCl

1.4 moles of Ca(OH)2

                           2HCl     +     Ca(OH)2    →        2H2O    +      CaCl2

MW                   2(36.5)               74                       36 g               111 g

                          73g                

                            1 mol of HCl ----------------  36.5 g

                           2.6 mol           --------------    x

                              x = (2.6 x 36.5) / 1   = 94.9 g

                           1 mol of Ca(OH)2 --------------   74 g

                         1.4 mol                  ---------------   x

                            x = (1.4 x 74) / 1  = 103.6 g

Grams of water

                        73 g of HCl ------------------   36g of H2O

                        94.9 g        -------------------    x

                     x = (94.9 x 36) / 73 = 46.8 g of water

6 0
3 years ago
Bromination occurs on alkene functional groups, but NOT on alkenes found within aromatic functional group, such as the phenyl ri
liq [111]

Answer:

When cinnamic acid react with bromine ,addition reaction rapidly occur on alkene functional group to form dibromo product

Explanation:

Phenyl ring is an aromatic hydrocarbon ,when aromatic hydrocarbons react with Cl2,Br2 or KMnO4 no reaction occur ,where as unsaturated hydrocarbon  like alkene react .Aromatic hydrocarbon with these reagents undenr different conditions undergoes subtituition reaction.They react with bromine in presence of lewis acid catalyst ferric bromide.

8 0
3 years ago
Which equation is used to help form the combined gas law? mc009-1. Jpg mc009-2. Jpg mc009-3. Jpg mc009-4. Jpg.
Luba_88 [7]

The combined gas law equation has been \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}.

The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.

In an ideal gas the equation has been given as:

PV=nRT

Where, <em>P </em>has been the pressure of the gas

<em>V </em>has been the volume of the gas

<em>n </em>has been the moles of the gas

<em>R </em>has been a constant

<em>T </em>has been the temperature of the gas

The combined gas law has been given as the change in the pressure, and volume for a gas. It has been given as:

\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}

For more information about combined gas law, refer to the link:

brainly.com/question/13154969

7 0
2 years ago
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